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If x is a positive integer, what is the median of the set of consecuti

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If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post 04 Apr 2016, 07:19
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If x is a positive integer, what is the median of the set of consecutive integers from 1 to x inclusive?

(1) The average of the set of integers from 1 to x inclusive is 11.

(2) The range of the set of integers from 1 to x inclusive is 20.

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If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post Updated on: 04 Apr 2016, 19:44
Statement 1 and 2 is sufficient. D is straight.
X+1=22
X=21.

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Originally posted by FightToSurvive on 04 Apr 2016, 11:55.
Last edited by FightToSurvive on 04 Apr 2016, 19:44, edited 1 time in total.
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Re: If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post 04 Apr 2016, 12:15
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St1: Average is 11 --> In a set of consecutive integers the mean is always equal to the median. Since we know the mean value as 11, the median value is also equal to 11. --> Sufficient

St2: Range = 20 --> Last term = 21 --> Mean = (First term + Last term)/2 = (1 + 21)/2 = 11 --> Median = 11 --> Sufficient

Answer: D
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Re: If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post 25 Jul 2017, 07:00
1. in a set of consecutive integers, the median is the mean in the same time. Sufficient.
2. since X is an integer, we can conclude that x is 21, therefore, knowing that we have a set of consecutive integers from 1 to 21, we can find the median. sufficient.

answer is D.
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Re: If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post 25 Jul 2017, 09:19
Bunuel wrote:
If x is a positive integer, what is the median of the set of consecutive integers from 1 to x inclusive?

(1) The average of the set of integers from 1 to x inclusive is 11.

(2) The range of the set of integers from 1 to x inclusive is 20.



1) mean=median is a property of evenly spaced sets and consecutive integers are special type of evenly spaced sets. Sufficient.
2)range= 20 that means x = 21 (x-1=20), since, (first term + last term)/2= mean = median in consecutive integers set. Hence sufficient. Thus, D.
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Re: If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post 10 Sep 2017, 23:00
Bunuel wrote:
If x is a positive integer, what is the median of the set of consecutive integers from 1 to x inclusive?

(1) The average of the set of integers from 1 to x inclusive is 11.

(2) The range of the set of integers from 1 to x inclusive is 20.


The median of a set of consecutive integers is always the same as the mean

St 1

Conforms to this rule

suff

St 2

suff

D
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Re: If x is a positive integer, what is the median of the set of consecuti [#permalink]

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New post 07 Dec 2017, 08:51
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Bunuel wrote:
If x is a positive integer, what is the median of the set of consecutive integers from 1 to x inclusive?

(1) The average of the set of integers from 1 to x inclusive is 11.

(2) The range of the set of integers from 1 to x inclusive is 20.


We are given that x is a positive integer, and we need to determine the median of the set of consecutive integers from 1 to x inclusive. We may recall that when we have an evenly spaced set (or in this case a set of consecutive integers), the average will always be equal to the median.

Statement One Alone:

The average of the set of integers from 1 to x inclusive is 11.

Since we know that the average is equal to 11, the median must also be equal to 11. Statement one alone is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone:

The range of the set of integers from 1 to x inclusive is 20.

Since we have a set of consecutive integers, and we know that the smallest number is 1 and the largest is 1 + 20 = 21, we can determine that the median is:

(21 + 1)/2 = 22/2 = 11

Statement two alone is also sufficient to answer the question.

Answer: D
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Re: If x is a positive integer, what is the median of the set of consecuti   [#permalink] 07 Dec 2017, 08:51
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