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If x is a positive integer, what is the value of x? (1) 2x = x! (2) x

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If x is a positive integer, what is the value of x? (1) 2x = x! (2) x  [#permalink]

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New post 06 Dec 2018, 05:50
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A
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C
D
E

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63% (00:59) correct 37% (01:01) wrong based on 112 sessions

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Re: If x is a positive integer, what is the value of x? (1) 2x = x! (2) x  [#permalink]

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New post 06 Dec 2018, 05:55
The answer is D.
1) this is not true for x=1 (2=1) or x=2 (4=2), for which the left side is greater. it is true for x=3 (6=6). for x=4 (8=24) the right side is greater, and we can easily see that as we progress, the right side will increase even more in relation to the left side. In other words, there is no way there will be another value that works - only x=3. sufficient!
2) x(x-3)=0 ==> x=0, x=3 - but since we know x is a positive integer, only x=3 works. Sufficient!
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Re: If x is a positive integer, what is the value of x? (1) 2x = x! (2) x  [#permalink]

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New post 06 Dec 2018, 06:12
Bunuel wrote:
If x is a positive integer, what is the value of x?

(1) 2x = x!
(2) x^2 - 3x = 0


x!= x * (x-1)

from 1
2x= x( x-1)
or x = 3 sufficient

From 2
we get x ( x-3)=0
x=0 and 3
since x is a +ve integer so x=3 is sufficient IMO D
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Re: If x is a positive integer, what is the value of x? (1) 2x = x! (2) x  [#permalink]

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New post 24 Dec 2018, 01:30
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Re: If x is a positive integer, what is the value of x? (1) 2x = x! (2) x   [#permalink] 24 Dec 2018, 01:30
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