Last visit was: 19 Nov 2025, 16:12 It is currently 19 Nov 2025, 16:12
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
guygmat
Joined: 18 Jun 2011
Last visit: 21 Jun 2011
Posts: 41
Own Kudos:
365
 [1]
Posts: 41
Kudos: 365
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
sudhir18n
User avatar
Current Student
Joined: 26 May 2005
Last visit: 13 Feb 2013
Posts: 352
Own Kudos:
604
 [1]
Given Kudos: 13
Posts: 352
Kudos: 604
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
sameershintrein
Joined: 10 May 2011
Last visit: 05 Jan 2012
Posts: 3
Own Kudos:
Given Kudos: 13
Posts: 3
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
sudhir18n
User avatar
Current Student
Joined: 26 May 2005
Last visit: 13 Feb 2013
Posts: 352
Own Kudos:
Given Kudos: 13
Posts: 352
Kudos: 604
Kudos
Add Kudos
Bookmarks
Bookmark this Post
sameershintrein
I did not get how the answer is B for this question.
Lets consider (2) x is divisible by 14.
Lets consider x=70 (Its divisible by 14) but 70*3 is not completely divisible by 49 so should answer be 'E' ?
Please clarify ...

its not 70*3 it shud be 70^3.
User avatar
l0rrie
Joined: 16 Mar 2011
Last visit: 26 Jun 2011
Posts: 117
Own Kudos:
Given Kudos: 13
Posts: 117
Kudos: 152
Kudos
Add Kudos
Bookmarks
Bookmark this Post
did not get how the answer is B for this question.
Lets consider (2) x is divisible by 14.
Lets consider x=70 (Its divisible by 14) but 70*3 is not completely divisible by 49 so should answer be 'E' ?
Please clarify ...


If you know x is divisible by 14 you know that x's prime factors must AT LEAST have a 7 and a 2.

No matter what the value for x will be, if you square x it means that x.x is divisible by 14(14) twice. So that gives us atleast two 7's and two 2's.. 2x7=49 which makes it sufficient.
User avatar
TomB
Joined: 18 Sep 2009
Last visit: 05 Jul 2013
Posts: 194
Own Kudos:
Given Kudos: 2
Posts: 194
Kudos: 3,051
Kudos
Add Kudos
Bookmarks
Bookmark this Post
same doubt as above post
User avatar
fluke
User avatar
Retired Moderator
Joined: 20 Dec 2010
Last visit: 24 Oct 2013
Posts: 1,099
Own Kudos:
Given Kudos: 376
Posts: 1,099
Kudos: 5,095
Kudos
Add Kudos
Bookmarks
Bookmark this Post
guygmat
If x is an integer, is x3 divisible by 49 ?

(1) x is divisible by 8.

(2) x is divisible by 14.

Please avoid the ambiguity by using proper math symbol. I have seen many people making the same mistake when representing the exponents.

The correct version of the question above should be:
*************************************************
If x is an integer, is x^3 divisible by 49 ?

(1) x is divisible by 8.

(2) x is divisible by 14.
*******************************************

Better use the m tag:
********************************************
If x is an integer, is \(x^3\) divisible by 49 ?

(1) x is divisible by 8.

(2) x is divisible by 14.
*********************************************
User avatar
gijoedude
Joined: 17 May 2010
Last visit: 13 Jul 2013
Posts: 197
Own Kudos:
Given Kudos: 7
GMAT 1: 710 Q47 V40
GMAT 1: 710 Q47 V40
Posts: 197
Kudos: 113
Kudos
Add Kudos
Bookmarks
Bookmark this Post
We need: to be divisible by 49, X3 needs to have atleast two 7s.

Stmt 1: X is divisible by 8. IE it's a multiple of 8. No 7. Insufficient.
Stmt 2: X is divisible by 14. IE it has 7 and 2 as its factors. X3 will have atleast three 7s. This satisfies our need.

Hence B it is.
User avatar
Spidy001
Joined: 01 Feb 2011
Last visit: 16 Feb 2015
Posts: 298
Own Kudos:
Given Kudos: 42
Posts: 298
Kudos: 348
Kudos
Add Kudos
Bookmarks
Bookmark this Post
1. not sufficient

as we dont know whether x has factor 7 in it or not.

if x has a factor 7 , then x^3 is divisible by 49 else no

2. sufficient

as we know x has a 7 , x^3 has 7^3 as a factor

hence x^3 is divisble by 49.

Answer is B.
User avatar
amit2k9
Joined: 08 May 2009
Last visit: 18 Jun 2017
Posts: 535
Own Kudos:
Given Kudos: 10
Status:There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Posts: 535
Kudos: 636
Kudos
Add Kudos
Bookmarks
Bookmark this Post
a 0 and 8 gives different values for 49. Hence not sufficient.

b 0 and 14^3 = 7^3 * 2^3
sufficient.

B it is.
User avatar
tenaman10
Joined: 08 Nov 2008
Last visit: 06 Jan 2012
Posts: 152
Own Kudos:
Given Kudos: 7
Posts: 152
Kudos: 1,295
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Dont u think that ans has to be D ..
option 1 :: x is divisible by 8
means x can be 8,16, 24 etc ..
In any of the case x^3 will not be divisible by 49 ..Means ans is NO ..thus sufficient .
Does it makes any sense ?
pls share yr views .
User avatar
Warlock007
Joined: 08 Jan 2011
Last visit: 25 May 2012
Posts: 149
Own Kudos:
Given Kudos: 46
Status:==GMAT Ninja==
Schools:ISB, IIMA ,SP Jain , XLRI
WE 1: Aditya Birla Group (sales)
WE 2: Saint Gobain Group (sales)
Posts: 149
Kudos: 224
Kudos
Add Kudos
Bookmarks
Bookmark this Post
guygmat
If \(x\)is an integer, is \(x^3\) divisible by \(49\)?

(1) \(x\)is divisible by \(8\).

(2) \(x\)is divisible by \(14\).


a Simple B for me

reason already explained by fellow users :) :)
User avatar
Chetangupta
Joined: 23 Jan 2011
Last visit: 04 Oct 2021
Posts: 82
Own Kudos:
Given Kudos: 13
Posts: 82
Kudos: 475
Kudos
Add Kudos
Bookmarks
Bookmark this Post
stmnt 1) x contains atleast three 2s, may or may not contain 7- not sufficient- A/D out
stmnt 2) x contains atleast one 2 and one 7. x^3 will contain atleast 3 two's and 3 seven's. this will be divisible by 7. B is the answer.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Math Expert
105390 posts
GMAT Tutor
1924 posts