It is currently 11 Dec 2017, 12:17

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If X is an integer, is Y an integer? (1) The average

Author Message
Intern
Joined: 29 Aug 2003
Posts: 29

Kudos [?]: 1 [0], given: 0

Location: Mumbai
If X is an integer, is Y an integer? (1) The average [#permalink]

### Show Tags

06 Dec 2003, 22:02
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

"If X is an integer, is Y an integer?

(1) The average (arithmetic mean) of X and Y is not an integer.

(2) X + Y = 2 (X - Y)
Statement 1 alone is sufficient but Statement 2 alone is NOT.
Statement 2 alone is sufficient but Statement 1 alone is NOT.
Statements 1 and 2 TOGETHER are sufficient but neither alone is.
EACH statement alone is sufficient,
NEITHER statement alone or combined is sufficient.

Kudos [?]: 1 [0], given: 0

Director
Joined: 28 Oct 2003
Posts: 501

Kudos [?]: 35 [0], given: 0

Location: 55405

### Show Tags

06 Dec 2003, 22:23
Quote:
"If X is an integer, is Y an integer?

Quote:
(1) The average (arithmetic mean) of X and Y is not an integer.

Insufficient.X and Y could be 1 and 2, for example.

Quote:
(2) X + Y = 2 (X - Y)

X+Y=2X-2Y
X+3Y=2X
X=3Y

Insufficient. If X is 1, Y is 1/3. If X is 3, Y is 1.

But, together, every combination of X and Y that satisfies condition 2 (examples):
X Y
3 1
6 2
9 3

Averages to an integer.

There are no (integer, integer) pairs that satisfy both conditions.

I say C.

Kudos [?]: 35 [0], given: 0

Director
Joined: 28 Oct 2003
Posts: 501

Kudos [?]: 35 [0], given: 0

Location: 55405

### Show Tags

06 Dec 2003, 22:26
Also, to satisfy condition 1, you need an even and an odd.

To satisfy condition 2, you need two odds or two evens.

No pair of integers can satisfy both conditions.

So I suppose that's a better shortcut.

Kudos [?]: 35 [0], given: 0

06 Dec 2003, 22:26
Display posts from previous: Sort by