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If x is an integer such that 2x + 1 < 3, then which of the following
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25 Apr 2018, 21:55
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If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)? I. 0 II. 6 III. 10 (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III
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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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25 Apr 2018, 22:16
Bunuel wrote: If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)?
I. 0 II. 6 III. 10
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III \(2x + 1 < 3\) \(3 < 2x + 1 < 3\) \(2 < x < 1\) \(x^3 + 2x^2 + 5x + 10\) expression can be written as \(A=(x^2+5)(x+2)\) So, in order to \(A\) to be equal to \(0\), \(x\) must be \(2\) which is not possible. When \(x=1\), \(A=6\) and when \(x=0\), \(A=10\). Hence, \(II\) and \(III\) are possible values of \(A\). Answer: D
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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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26 Apr 2018, 00:49
Bunuel wrote: If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)?
I. 0 II. 6 III. 10
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III Ans: D Given : 2x+1<3 ; means −3<2x+1<3 : further −2<x<1 because x an int and lies between 2 and 1 exclusive it can have only two values 0 and 1. by putting it in equation we get 10 and 6. hence D is the ans.
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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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26 Apr 2018, 11:46
2x+1<3 which means 4<2x<2 2<x<1 so x can take two values : 1 and 0 apply each value of x to x^3+2x^2+5x+10 for 0 we will get 10 for 1 we will get 6 so option D is the right answer



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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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27 Apr 2018, 09:58
Bunuel wrote: If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)?
I. 0 II. 6 III. 10
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III We are given that x is an integer and that 2x + 1 < 3. We first solve for x by considering two cases: Case 1: 2x + 1 < 3 2x < 2 x < 1. Case 2: 2x + 1 > 3 2x > 4 x 2 Thus, we see that 2 < x < 1. The only integers that satisfy this inequality are 0 and 1. If x = 0: x^3 + 2x^2 + 5x + 10 = 10 If x = 1: x^3 + 2x^2 + 5x + 10 = 1 + 2  5 + 10 = 6 Answer: D
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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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27 Apr 2018, 11:14
Bunuel wrote: If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)?
I. 0 II. 6 III. 10
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III The give inequality is 2x + 1 <3 ==>3<2x + 1<3 ==> 31<2x<31 ==> 4<2x<2 ==> 2<x<1 Since the x is an integer, the value of x will be 1 and 0 And for x = 1 the value of the expression is 6 for x = 0 the value of the expression is 11 Hence the answer will be (D)



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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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23 May 2018, 20:19
ScottTargetTestPrep wrote: Bunuel wrote: If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)?
I. 0 II. 6 III. 10
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III We are given that x is an integer and that 2x + 1 < 3. We first solve for x by considering two cases: Case 1: 2x + 1 < 3 2x < 2 x < 1. Case 2: 2x + 1 > 3 2x > 4 x 2 Thus, we see that 2 < x < 1. The only integers that satisfy this inequality are 0 and 1. If x = 0: x^3 + 2x^2 + 5x + 10 = 10 If x = 1: x^3 + 2x^2 + 5x + 10 = 1 + 2  5 + 10 = 6 Answer: D Hello, i was solving another problem  If x^2 − 12 = x, which of the following could be the value of x? : Problem Solving (PS) You provided a solution on this question and explained that value of x^212 will be +ve. Then how  2x1 can have + and  value. Posted from my mobile device



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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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23 May 2018, 20:36
x>2 and x<1. Therefore, x = 0 or x = 1, as x is an integer. Replacing x in equation, hence, value = 6 or value = 10 D Sent from my iPhone using GMAT Club Forum mobile app



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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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23 May 2018, 21:00
Bunuel wrote: If x is an integer such that \(2x + 1 < 3\), then which of the following is a possible value of \(x^3 + 2x^2 + 5x + 10\)?
I. 0 II. 6 III. 10
(A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, III Solution : We need to follow below example: x = 2. Then we always write 2 < x < 2. That is value of x ranges from 2 to 2. Similarly, 2x+1<3 can be written as −3<2x+1<3 −31<2x<31 4<2x<2 2<x<1. Possible values of x is 1 and 0. Substitute in the expression given to get the answer. \(x^3 + 2x^2 + 5x + 10\). Let's put x = 1 \((1)^3 + 2(1)^2 + 5(1) + 10\) = 1+25+10 = 126 = 6. Let's put x =0. Clearly expression gives output as 10. So, 6 & 10 is right ans. Ans D
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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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Re: If x is an integer such that 2x + 1 < 3, then which of the following
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