If x is not equal to 0, is x^2 + 1 / x y? (I) x = y (2)

Question

If x is not equal to 0, is x^2 + 1 / x > y?

(I) x = y

(2) y > 0

OA is  C

nik1608nik · Answer

it should be B alone is able to ans the question.

bigtreezl · Answer

the question is written as (x^2) + (1/x) > y ? is this correct? if so I get A

pmenon · Answer

im with bigtreezl, I get A as well, assuming that the equation in the question is as bigtreezl has written it.

ngoctraiden1905 · Answer

1/ y^2+1/y-y>0
With y=2 and y= -0.3 => insuf
2/ x^2+1/x can be (+) or (-) with x = 2 or -0.3. With the info y>0 => insuf
together suf, hence C

Hades · Answer

Question: (x^2 + 1 / x > y)?

(1)  x=y

Question: (x^2 + 1 / x > x)? 
Question: (x^3 + 1 > x^{2})? 
Question: (1 > x^{2} - x^{3})? 
Question: (1 > x^{2}(1 - x)?

If x<-1 NO
If x>0 YES

(2) y>0 insufficient

(1&2)
 x=y>0 \longrightarrow x>0 
Question: (1 > x^{2}(1 - x)? 
 \longrightarrow ALWAYS YES

Final Answer,  C

skim · Answer

The equation in question is:

If x is not equal to 0, is 
 x^2+1 
x 
> y ?
 
(1) x = y
(2) y > 0

mdfrahim · Answer

C.

Stmt 1 - Can be written as

Is (X) + (1/X) > (X) -----------------> 1
We can see that (1/X) can raise the value of LHS if X is +ve or it can lower the value if X is -ve.
So not suff.

Stmt 2 - 
Does not talk abt. X. So not suff.

Combine....
Stmt 1 tells X=Y and Stmt. 2 tells that X is +ve(because y is +ve)
apply this info. to eq. 1
Clearly suff.

If x is not equal to 0, is x^2 + 1 / x > y? (I) x = y (2)

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