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# If x is not equal to 0, is x^2 + 1 / x > y? (I) x = y (2)

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Manager
Joined: 28 Mar 2009
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If x is not equal to 0, is x^2 + 1 / x > y? (I) x = y (2) [#permalink]

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08 Jun 2009, 06:41
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If x is not equal to 0, is x^2 + 1 / x > y?

(I) x = y

(2) y > 0

OA is
[Reveal] Spoiler:
C

Kudos [?]: 368 [0], given: 0

Intern
Joined: 28 Feb 2009
Posts: 28

Kudos [?]: 9 [0], given: 8

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08 Jun 2009, 12:30
it should be B alone is able to ans the question.

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Director
Joined: 23 May 2008
Posts: 801

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08 Jun 2009, 14:52
nik1608nik wrote:
it should be B alone is able to ans the question.

the question is written as (x^2) + (1/x) > y ? is this correct? if so I get A

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SVP
Joined: 28 Dec 2005
Posts: 1545

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08 Jun 2009, 17:01
im with bigtreezl, I get A as well, assuming that the equation in the question is as bigtreezl has written it.

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Manager
Joined: 11 Aug 2008
Posts: 150

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08 Jun 2009, 17:49
1/ y^2+1/y-y>0
With y=2 and y= -0.3 => insuf
2/ x^2+1/x can be (+) or (-) with x = 2 or -0.3. With the info y>0 => insuf
together suf, hence C

Kudos [?]: 54 [0], given: 8

Manager
Joined: 14 May 2009
Posts: 191

Kudos [?]: 48 [0], given: 1

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08 Jun 2009, 18:05
skim wrote:
If x is not equal to 0, is x^2 + 1 / x > y?

(I) x = y

(2) y > 0

OA is
[Reveal] Spoiler:
C

Question:$$(x^2 + 1 / x > y)?$$

(1) $$x=y$$

Question:$$(x^2 + 1 / x > x)?$$
Question:$$(x^3 + 1 > x^{2})?$$
Question:$$(1 > x^{2} - x^{3})?$$
Question:$$(1 > x^{2}(1 - x)?$$

If x<-1 NO
If x>0 YES

(2) y>0 insufficient

(1&2)
$$x=y>0 \longrightarrow x>0$$
Question:$$(1 > x^{2}(1 - x)?$$
$$\longrightarrow ALWAYS YES$$

Final Answer, $$C$$
_________________

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Manager
Joined: 28 Mar 2009
Posts: 74

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09 Jun 2009, 03:02
The equation in question is:

If x is not equal to 0, is
x^2+1
x
> y ?

(1) x = y
(2) y > 0

pmenon wrote:
im with bigtreezl, I get A as well, assuming that the equation in the question is as bigtreezl has written it.

Kudos [?]: 368 [0], given: 0

Manager
Joined: 28 Jan 2004
Posts: 202

Kudos [?]: 28 [0], given: 4

Location: India

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09 Jun 2009, 23:00
C.

Stmt 1 - Can be written as

Is (X) + (1/X) > (X) -----------------> 1
We can see that (1/X) can raise the value of LHS if X is +ve or it can lower the value if X is -ve.
So not suff.

Stmt 2 -
Does not talk abt. X. So not suff.

Combine....
Stmt 1 tells X=Y and Stmt. 2 tells that X is +ve(because y is +ve)
apply this info. to eq. 1
Clearly suff.

Kudos [?]: 28 [0], given: 4

Re: Inequalities (IV)   [#permalink] 09 Jun 2009, 23:00
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