Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1410:00 AM PDT
-11:59 PM PDT
GMAT Preparation Online - A limited time sale use code: EXPERTSGLOBAL10- Jul 15
08:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations! 
Jul 1609:30 AM EDT
-11:30 AM EDT
Is INSEAD your dream b-school and you're looking for solid prep and application strategies to get there? Check out Barkavi’s end-to-end journey to know how she did! Get insights into the INSEAD admissions process, know what Adcoms look at, and more!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Jul 1911:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
20 Mar 2022, 02:58
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
45% (02:33) correct
55%
(02:54)
wrong
based on 89
sessions
History
Date
Time
Result
Not Attempted Yet
If x is not equal to |y|, is \(\frac{x-y}{x+y} > \frac{x+y}{x-y}\)?
(1) \(x > y^2\)
(2) \(x^2>y>0\)
Are You Up For the Challenge: 700 Level Questions
(1) \(x > y^2\)
(2) \(x^2>y>0\)
Are You Up For the Challenge: 700 Level Questions
PyjamaScientist
Admitted - Which School Forum Moderator
Joined: 25 Oct 2020
Last visit: 15 May 2025
Posts: 1,118
Given Kudos: 633
Schools: Ross '25 (M$)
GMAT 1: 740 Q49 V42 (Online)
Products:
02 May 2022, 11:22
Kudos
Bookmarks
Bunuel
If x is not equal to |y|, is \(\frac{x-y}{x+y} > \frac{x+y}{x-y}\)?
(1) \(x > y^2\)
(2) \(x^2>y>0\)
Are You Up For the Challenge: 700 Level Questions
Is \(\frac{x-y}{x+y} > \frac{x+y}{x-y}\)?(1) \(x > y^2\)
(2) \(x^2>y>0\)
Are You Up For the Challenge: 700 Level Questions
(I) \(x>y^2\)
This gives, \(x>y \) or \(x-y>0\). But what about \(x+y\)? What if \(y=-4\) and \(x=4\). That would give \(x+y=0\) And the L.H.S would become not defined. So, this alone is insufficient.
(II) \(x^2>y>0\)
This can lead to three possibilities,
Case (A) \(x<y (x=2,y=3,x^2=4)\)
In this case, is \(\frac{x-y}{x+y} > \frac{x+y}{x-y}\) = \(\frac{2-3}{2+3} > \frac{2+3}{2-3}\) = \(\frac{-1}{5} > \frac{-5}{1}\). So, Yes! \(\frac{x-y}{x+y} > \frac{x+y}{x-y} \) holds.
Case (B) \(x=y (x=2,y=2)\)
For this x-y = 2-2= 0. This makes R.H.S not defined. Not possible.
Case (C)\(x>y (x=3,y=2)\)
\(\frac{x-y}{x+y} > \frac{x+y}{x-y}\) = \(\frac{3-2}{3+2} > \frac{3+2}{3-2}\) = \(\frac{1}{5} > \frac{5}{1}\)? No! \(\frac{x-y}{x+y} > \frac{x+y}{x-y}\) does not hold.
Thus, insufficient, since cases (A) and (C) give contradictory answers.
(I) + (II) = \(x>y\)
In that case (C) gives a definite unique answer=No. Thus, both are sufficient together.
So, answer is option (C).
