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if x is NOT = to -y is x-y/x+y => 1 1. x > 0 2. y <

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Senior Manager
Joined: 05 Oct 2008
Posts: 270

Kudos [?]: 537 [0], given: 22

if x is NOT = to -y is x-y/x+y => 1 1. x > 0 2. y < [#permalink]

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16 Nov 2008, 06:45
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

if x is NOT = to -y is x-y/x+y => 1

1. x > 0
2. y < 0

Kudos [?]: 537 [0], given: 22

Intern
Joined: 03 Oct 2008
Posts: 17

Kudos [?]: 1 [0], given: 0

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16 Nov 2008, 07:10
x-y/x+y => 1

0 => y

st 1.
x > 0,insuff.

st 2.
y < 0 , suff.

Is b the ans.

Kudos [?]: 1 [0], given: 0

Intern
Joined: 26 May 2008
Posts: 34

Kudos [?]: 6 [0], given: 0

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16 Nov 2008, 15:35
This will have to be E.

You need to satisfy two conditions for (x-y)/(x+y) to be >=1.

1) Both (x-y) and (x+y) have to be of the same sign.

2) The absolute value of (x-y) must be >= the absolute value of (x+y).

Now A and B each taken separately give you info about x or y. So they are INSUFF.

Taken together, you only know that x-y is always positive. But how about x+y?

x=7 and y=-3 then you get an YES for the question.

x=3 and y=-7 the you get a NO.

So it is E.

Kudos [?]: 6 [0], given: 0

VP
Joined: 05 Jul 2008
Posts: 1402

Kudos [?]: 437 [0], given: 1

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16 Nov 2008, 16:35
got an E as well

(x-y) > = (x+y)

-2y > = 0

means

Is y <= 0?

A) insuff

B) Y < 0 Insuff

Together Insuff E

Kudos [?]: 437 [0], given: 1

Manager
Joined: 09 Jul 2008
Posts: 111

Kudos [?]: 42 [0], given: 1

Location: Dallas, TX
Schools: McCombs 2011

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16 Nov 2008, 19:50
Is $$\frac{x-y}{x+y} >= 1 ?$$

$$\frac{x-y}{x+y} - 1>= 0 ?$$

$$\frac{x-y-x-y}{x+y} >= 0 ?$$

$$\frac{-2y}{x+y} >= 0 ?$$

(1) x>0
INSUFF because no info about y

(2) y<0
INSUFF because no info about x

1 and 2 combined INSUFF, we know that numerator is > 0. But, x+y cannot be determined. Should be E.

Kudos [?]: 42 [0], given: 1

Re: No. Properties   [#permalink] 16 Nov 2008, 19:50
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