Last visit was: 19 Nov 2025, 04:02 It is currently 19 Nov 2025, 04:02
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,379
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,379
Kudos: 778,194
 [21]
Kudos
Add Kudos
20
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
nick1816
User avatar
Retired Moderator
Joined: 19 Oct 2018
Last visit: 06 Nov 2025
Posts: 1,849
Own Kudos:
8,237
 [9]
Given Kudos: 707
Location: India
Posts: 1,849
Kudos: 8,237
 [9]
5
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
General Discussion
User avatar
ArunSharma12
Joined: 25 Oct 2015
Last visit: 20 Jul 2022
Posts: 513
Own Kudos:
1,019
 [1]
Given Kudos: 74
Location: India
GMAT 1: 650 Q48 V31
GMAT 2: 720 Q49 V38 (Online)
GPA: 4
Products:
GMAT 2: 720 Q49 V38 (Online)
Posts: 513
Kudos: 1,019
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 19 Nov 2025
Posts: 5,794
Own Kudos:
Given Kudos: 161
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,794
Kudos: 5,509
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If x is positive, what is the least possible value of \(\frac{x}{2} + \frac{2}{x}\)?

(A) 1/2
(B) 1
(C) 2
(D) 3
(E) 4


Are You Up For the Challenge: 700 Level Questions

\(\frac{x}{2} + \frac{2}{x} - 2*\sqrt{x/2}\sqrt{2/x} = (\sqrt{x/2}- \sqrt{2/x})^2 >0\)
\(\frac{x}{2} + \frac{2}{x} > 2\)

IMO C
User avatar
Kritisood
Joined: 21 Feb 2017
Last visit: 19 Jul 2023
Posts: 492
Own Kudos:
1,271
 [2]
Given Kudos: 1,090
Location: India
GMAT 1: 700 Q47 V39
Products:
GMAT 1: 700 Q47 V39
Posts: 492
Kudos: 1,271
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
nick1816
AM ≥ GM

\((\frac{x}{2} + \frac{2}{x})/2 ≥ \sqrt{\frac{x}{2}*\frac{2}{x}}\)

\((\frac{x}{2} + \frac{2}{x})/2 ≥ 1\)

\((\frac{x}{2} + \frac{2}{x}) ≥ 2\)

C

Bunuel
If x is positive, what is the least possible value of \(\frac{x}{2} + \frac{2}{x}\)?

(A) 1/2
(B) 1
(C) 2
(D) 3
(E) 4


Are You Up For the Challenge: 700 Level Questions

Hi, could you please elaborate on your approach? Is there a definite way to solve such min/max problems??
User avatar
nick1816
User avatar
Retired Moderator
Joined: 19 Oct 2018
Last visit: 06 Nov 2025
Posts: 1,849
Own Kudos:
8,237
 [2]
Given Kudos: 707
Location: India
Posts: 1,849
Kudos: 8,237
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Assume x and y are 2 positive numbers

\((x-y)^2 ≥ 0\)

\((x+y)^2 - 4xy ≥ 0\)

\((x+y)^2 ≥ 4xy\)

\(\frac{(x+y)^2}{4} ≥ xy\)

\(\frac{x+y}{2} ≥ \sqrt{xy}\), where x,y>0

arithmetic mean ≥ geometric mean



Since x is positive in the question, 2/x and x/2 >0. You can use the above inequality.



Kritisood
nick1816
AM ≥ GM

\((\frac{x}{2} + \frac{2}{x})/2 ≥ \sqrt{\frac{x}{2}*\frac{2}{x}}\)

\((\frac{x}{2} + \frac{2}{x})/2 ≥ 1\)

\((\frac{x}{2} + \frac{2}{x}) ≥ 2\)

C

Bunuel
If x is positive, what is the least possible value of \(\frac{x}{2} + \frac{2}{x}\)?

(A) 1/2
(B) 1
(C) 2
(D) 3
(E) 4


Are You Up For the Challenge: 700 Level Questions

Hi, could you please elaborate on your approach? Is there a definite way to solve such min/max problems??
User avatar
bellbell
Joined: 26 Aug 2022
Last visit: 18 Dec 2022
Posts: 33
Own Kudos:
Given Kudos: 37
Posts: 33
Kudos: 35
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Another approach:
Set x/2 + 2/x = y
(x^2+4)/2x=y
x^2-2xy+4=0
x^2-2xy+y^2-y^2+4=0
(x-y)^2-y^2+4=0
Since (x-y)^2 min = 0
=> y^2=4
=>y=2
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,583
Own Kudos:
Posts: 38,583
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105379 posts
Tuck School Moderator
805 posts