Last visit was: 15 Dec 2024, 12:34 It is currently 15 Dec 2024, 12:34
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
nick1816
User avatar
Retired Moderator
Joined: 19 Oct 2018
Last visit: 15 Dec 2024
Posts: 1,859
Own Kudos:
7,098
 []
Given Kudos: 707
Location: India
Posts: 1,859
Kudos: 7,098
 []
5
Kudos
Add Kudos
21
Bookmarks
Bookmark this Post
User avatar
PKN
Joined: 01 Oct 2017
Last visit: 20 Apr 2023
Posts: 821
Own Kudos:
1,436
 []
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 821
Kudos: 1,436
 []
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
sach24x7
Joined: 15 Aug 2014
Last visit: 15 Mar 2020
Posts: 77
Own Kudos:
74
 []
Given Kudos: 124
Status:Don't Give Up!
Location: India
Concentration: Operations, General Management
GMAT Date: 04-25-2015
WE:Engineering (Manufacturing)
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
avatar
emonmisra
Joined: 14 Jan 2019
Last visit: 12 Feb 2020
Posts: 5
Own Kudos:
2
 []
Given Kudos: 10
Posts: 5
Kudos: 2
 []
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
First plug in option a, x+y = 22 it gives IxI negative which is not possible
same with option b, it give IxI is negative
then plug in option c, you get IxI = 6 then consider x= 6, you get y = -4 and put these values in 2nd equation LHS matches with RHS

So that is right answer
Option C
User avatar
ronaldoSuiiii
Joined: 11 Jan 2022
Last visit: 19 Oct 2022
Posts: 18
Own Kudos:
Given Kudos: 75
Posts: 18
Kudos: 4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PKN
nick1816
If |x| + x + y = 8
and x + |y| - y = 14
Then what is the value of (x+y)

A. 22
B. 12
C. 2
D. 6
E. 15

When x>0 and y<0, we have |x|=x and |y|=-y.

(1) |x| + x + y = 8 or 2x+y=8
(2) x + |y| - y = 14 or x-2y=14

Solving eq(1) and (2), we have x=6 and y=-4.

Therefore, x+y=6+(-4)=2

Ans. (C)







If I put in your signs, why is it not

(1) |x| + x + (- y) = 8 or 2x-y=8
(2) x + |y| - (-y) = 14 or x+2y=14 ???

Because |y| will be positive after all.
User avatar
GMATGuruNY
Joined: 04 Aug 2010
Last visit: 14 Dec 2024
Posts: 1,336
Own Kudos:
3,415
 []
Given Kudos: 9
Schools:Dartmouth College
Expert reply
Posts: 1,336
Kudos: 3,415
 []
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
nick1816
If |x| + x + y = 8
and x + |y| - y = 14
Then what is the value of (x+y)

A. 22
B. 12
C. 2
D. 6
E. 15

We can PLUG IN THE ANSWERS, which represent the value of x+y.

|x| + x + y = 8
|x| = 8 - (x+y)
Since an absolute value cannot be negative, the greatest possible value for x+y is 8.
Eliminate A, B and E.

C: x+y = 2
Substituting x+y = 2 into |x| = 8 - (x+y), we get:
|x| = 8 - 2
|x| = 6
x = ±6
If x=6, then x+y=2 implies that y=-4.
Plugging x=6 and y=-4 into x + |y| - y = 14, we get:
6 + |-4| - (-4) = 14
14 = 14
Success!

User avatar
Regor60
Joined: 21 Nov 2021
Last visit: 12 Dec 2024
Posts: 484
Own Kudos:
Given Kudos: 399
Posts: 484
Kudos: 283
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ronaldoSuiiii

If I put in your signs, why is it not

(1) |x| + x + (- y) = 8 or 2x-y=8
(2) x + |y| - (-y) = 14 or x+2y=14 ???

Because |y| will be positive after all.

By putting the negative sign in front of Y you are changing the operation to a subtraction of Y in the first case and an addition in the second.

Posted from my mobile device
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 35,836
Own Kudos:
Posts: 35,836
Kudos: 930
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderator:
Math Expert
97886 posts