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# If x + y >0, is x > |y|? (1) x > y (2) y < 0

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Director
Joined: 03 Jul 2003
Posts: 651

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If x + y >0, is x > |y|? (1) x > y (2) y < 0 [#permalink]

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13 Dec 2003, 21:43
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If x + y >0, is x > |y|?

(1) x > y
(2) y < 0

Kudos [?]: 106 [0], given: 0

CEO
Joined: 15 Aug 2003
Posts: 3452

Kudos [?]: 924 [0], given: 781

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13 Dec 2003, 22:45
If x + y >0, is x > |y|?

(1) x > y
(2) y < 0

From stem, We know x> -y

Simply, does x satisfy x >y?

1... is sufficient.

2... not sufficient

A

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Director
Joined: 13 Nov 2003
Posts: 957

Kudos [?]: 178 [0], given: 0

Location: Florida

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13 Dec 2003, 23:31
we got X>-Y
A tells, X>Y

cool, we know it 's A

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Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 59 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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13 Dec 2003, 23:35
I got A.

1) suffish

2) insuffish

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Director
Joined: 13 Nov 2003
Posts: 788

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Location: BULGARIA

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14 Dec 2003, 05:13
If y<0 then from x+y>0 follows that x>-(-Y) or x>y, and x>-y, or x>IyI if y=-5, x=6..IMO should be D..

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Director
Joined: 03 Jul 2003
Posts: 651

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16 Dec 2003, 13:57

Anyone want to explain why (2) is sufficient ?

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Director
Joined: 28 Oct 2003
Posts: 501

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Location: 55405

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16 Dec 2003, 14:06
If Y is negative, and added to X to get a positive result, then x must be "bigger" than Y is "small"

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Director
Joined: 28 Oct 2003
Posts: 501

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Location: 55405

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16 Dec 2003, 14:09
Hey, BG, If you'd like, you can use shift-\, or | to denote absolute value.

It's the key just below backspcae...

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Director
Joined: 14 Oct 2003
Posts: 582

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Location: On Vacation at My Crawford, Texas Ranch

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16 Dec 2003, 14:38
I completely overlooked (2)

Question Stem

X+Y>0 Therefore, X>-Y. Thus, it is unclear if Y is a positive number or a negative number. If Y is a positive number, Then X could be positive or negative. However, if Y is negative then X MUST be positive - given the assumption X>-Y. Number 2 tells us that Y is a negative number. Thus X>-(-Y) = X>|Y|. This is a "Yes/No" question - number 2 allows to answer a definitive "Yes"!

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Manager
Joined: 26 Aug 2003
Posts: 232

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Location: United States

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17 Dec 2003, 06:50

Anyone want to explain why (2) is sufficient ?

Statement 2 tells us that y is negative. The statement in the original problem tells us x + y > 0. So if y is negative, according to Stmnt2, then for [x + y > 0] be true x has to be a little more than absolute value of y. And that answers question.

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17 Dec 2003, 06:50
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