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30 Mar 2016, 04:04
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D
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If \(\sqrt{x+y}= 4\) and \(\sqrt{x – y} = 0\), what is x?
A. 0
B. 2
C. 4
D. 8
E. 16
A. 0
B. 2
C. 4
D. 8
E. 16
31 Mar 2016, 05:22
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Bookmarks
Bunuel
If \(\sqrt{x+y}= 4\) and \(\sqrt{x – y} = 0\), what is x?
A. 0
B. 2
C. 4
D. 8
E. 16
A. 0
B. 2
C. 4
D. 8
E. 16
\(\sqrt{x + y} = 4\) - (i)
\(\sqrt{x – y} = 0\) - (ii)
On squaring (i) and (ii)
x + y = 16
x - y = 0
Adding these two, 2x = 16
x = 8
Option D
31 Mar 2016, 05:29
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Bunuel
If \(\sqrt{x+y}= 4\) and \(\sqrt{x – y} = 0\), what is x?
A. 0
B. 2
C. 4
D. 8
E. 16
A. 0
B. 2
C. 4
D. 8
E. 16
Hi,
Another thought process..
\(\sqrt{x – y} = 0\), POSSIBLE only when x=y...
substitute x=y in \(\sqrt{x+y}= 4\)
\(\sqrt{x+x}= 4\) ..
\(\sqrt{2x}= 4\) so 2x=16 OR x=8
D
