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15 Dec 2018, 08:40
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D
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Difficulty:
5%
(low)
Question Stats:
96% (00:23) correct
4%
(00:38)
wrong
based on 601
sessions
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If \(\frac{x}{y} = 2\), then \(\frac{(x-y)}{y}\) =
(A) \(-1\)
(B) \(-\frac{1}{2}\)
(C) \(\frac{1}{2}\)
(D) \(1\)
(E) \(2\)
(A) \(-1\)
(B) \(-\frac{1}{2}\)
(C) \(\frac{1}{2}\)
(D) \(1\)
(E) \(2\)
15 Dec 2018, 08:52
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[quote="HKD1710"]if \(\frac{x}{y} = 2\), then \(\frac{(x-y)}{y}\) =
(A) \(-1\)
(B) \(-\frac{1}{2}\)
(C) \(\frac{1}{2}\)
(D) \(1\)
(E) \(2\)
X/Y = 2,
X - Y /Y = X/ Y - 1
2- 1 = 1
Choice D
(A) \(-1\)
(B) \(-\frac{1}{2}\)
(C) \(\frac{1}{2}\)
(D) \(1\)
(E) \(2\)
X/Y = 2,
X - Y /Y = X/ Y - 1
2- 1 = 1
Choice D
15 Dec 2018, 09:02
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HKD1710
APPROACH #1: Use the fact that (a - b)/c = a/b - b/c
So, (x - y)/y = x/y - y/y
= x/y - 1
= 2 - 1
= 1
Answer: D
APPROACH #2: Plug in values.
If x/y = 2, then it could be the case that x = 6 and y = 3
So, (x - y)/y = (6 - 3)/3
= 3/3
= 1
Answer: D
Cheers,
Brent
