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milind1979
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milind1979
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lav
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selvae
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Agree with B

x + y = integer -- 1) is Y an integer?

1)
x - y = int1 --- 2)

so solving both 1 and 2, we get 2y = int2 - int1
So we can say weather Y is an integer. coz (int2 - int1)/2 may not be an integer.

2) x + y + y = integer

So y is definely an integer integer - integer

B
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ritula
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My choice is also B

given x+y=integer-----(1)

Statement 1: x-y=integer-----------(2)
(1)-(2) --------> 2y=integer
now y may be an integer or may not be eg if y=2.5 still 2y=5 an integer Insuff

Statemnet 2: x+2y=intger
x+y+y =integer
now x+y=integer
hence y=integer Suff
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pmenon
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What about the case where x=1.5 and y=0.5 ? In this case, x+y is an integer, and x+2y also gives an integer even when y is not an integer. You could also have x=1 and y=2, and again x+y gives an integer, as does x+2y .... so how can it be B ?
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lav
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when x=1.5 and y=0.5 ... In this case, x+y is an integer = 2
BUT x+2y gives 1.5 + 1.0 = 2.5 hence not an integeer
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ritula
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x+2y= 2.5 ---------> not an integer

pmenon
What about the case where x=1.5 and y=0.5 ? In this case, x+y is an integer, and x+2y also gives an integer even when y is not an integer. You could also have x=1 and y=2, and again x+y gives an integer, as does x+2y .... so how can it be B ?



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