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If x-y= R and xy=S, then (x-2)(y+2)=

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If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 23 Jul 2017, 09:21
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Re: If x-y= R and xy=S, then (x-2)(y-2)=  [#permalink]

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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 24 Jul 2017, 20:47
carcass wrote:
If x-y= R and xy=S, then (x-2)(y+2)=

A. R+S-4

B. R+2S -4

C. 2R - S -4

D. 2R + S - 4

E. R + S

(x-2)(y+2) = xy +2x - 2y -4
=xy +2(x-y) -4
=S + 2R - 4

Answer D
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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 24 Jul 2017, 21:19
(x-2) (y+2) = xy - 2y + 2x - 4

x-y = R, xy = S

xy - 2y + 2x - 4 = S + 2(x-y) - 4 = S + 2R - 4. Ans - D.
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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 24 Jul 2017, 21:58
carcass wrote:
If x-y= R and xy=S, then (x-2)(y+2)=

A. R+S-4

B. R+2S -4

C. 2R - S -4

D. 2R + S - 4

E. R + S


x-y = R
xy = S
(x-2)(y+2) = xy - 2y + 2x -4 = xy + 2(x-y) - 4
= S + 2R - 4

Answer D
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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 26 Jul 2017, 15:16
carcass wrote:
If x-y= R and xy=S, then (x-2)(y+2)=

A. R+S-4

B. R+2S -4

C. 2R - S -4

D. 2R + S - 4

E. R + S


(x-2)(y+2)

= xy + 2x - 2y - 4

= xy + 2(x - y) - 4

= S + 2R - 4

Answer: D
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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 27 Aug 2017, 23:14
I made a frivulous mistake in hurry and picked B.

I solved xy+2(x-y)-4
But in hurry picked R+2S-4 Instead of S+2R-4.
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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 05 Sep 2017, 05:05
1. (x-2)(y+2)
2. xy + 2x -2y - 4 (order of operations/multiplication/parenthesis)

3. xy = S; 2x - 2y = 2R, for R = x - y; and - 4 stays the same
4. xy + 2x - 2y - 4 ----> S + 2R - 4

Ans = (D) 2R + S - 4
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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 18 Mar 2018, 11:15
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carcass wrote:
If x-y= R and xy=S, then (x-2)(y+2) =

A. R+S-4

B. R+2S -4

C. 2R - S -4

D. 2R + S - 4

E. R + S


Another approach is to assign some values for x and y.

Let's say that x = 5 and y = 2
This means R = 3 and S = 10

We must determine the value of (x - 2)(y + 2)
Plug in x = 5 and y = 2 to get: (x - 2)(y + 2) = (5 - 2)(2 + 2) = (3)(4) = 12

Now take each answer choices to see which one gives us an OUTPUT of 12.

A. R + S - 4 = 3 + 10 - 4 = 9. ELIMINATE

B. R + 2S - 4 = 3 + 2(10) - 4 =19. ELIMINATE

C. 2R - S - 4 = 2(3) - 10 - 4 = -8. ELIMINATE

D. 2R + S - 4 = 2(3) + 10 - 4 = 12 KEEP

E. R + S = 3 + 10 = 13. ELIMINATE

Answer: D

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Re: If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 06 Sep 2018, 08:32
\((x-2)(y+2)=xy+2x-2y-4\)
\(xy+2(x-y)-4\)
\(S+2R-4\)
\(2R+S-4\)

Answer D
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If x-y= R and xy=S, then (x-2)(y+2)=  [#permalink]

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New post 08 Sep 2018, 16:19
Let x=2 and y=1. Then: 2-1=1 (R) and 2*1=2 (S).

(x−2)(y+2) = (2−2)(1+2) = 0.

So we know that when 1 = (R) and 2 = (S), the equation = 0. Option D: 2R+S−4 = 2*1+2-4 = 0.
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If x-y= R and xy=S, then (x-2)(y+2)= &nbs [#permalink] 08 Sep 2018, 16:19
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