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Re: If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ? [#permalink]
Bunuel wrote:
If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ?

A. 1/25
B. 1/6
C. 1/5
D. 5
E. 6


Bunuel, will you please provide the solution?

I don't understand the solution above either. Thanks in advance.
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Re: If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ? [#permalink]
Expert Reply
msurls wrote:
Bunuel wrote:
If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ?

A. 1/25
B. 1/6
C. 1/5
D. 5
E. 6


Bunuel, will you please provide the solution?

I don't understand the solution above either. Thanks in advance.


\(\frac{1}{x} + \frac{1}{y} = 5\);

\(\frac{x+y}{xy} = 5\);

Since given that \(\frac{1}{xy}= 6\), then \(6(x+y)=5\).

Divide by 30: \(\frac{x+y}{5}=\frac{1}{6}\).

Answer: B.
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If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ? [#permalink]
Bunuel wrote:
msurls wrote:
Bunuel wrote:
If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ?

A. 1/25
B. 1/6
C. 1/5
D. 5
E. 6


Bunuel, will you please provide the solution?

I don't understand the solution above either. Thanks in advance.


\(\frac{1}{x} + \frac{1}{y} = 5\);

\(\frac{x+y}{xy} = 5\);

Since given that \(\frac{1}{xy}= 6\), then \(6(x+y)=5\).

Divide by 30: \(\frac{x+y}{5}=\frac{1}{6}\).

Answer: B.


My approach is pretty similar:

\(\frac{1}{x} + \frac{1}{y} = 5\);

\(\frac{x+y}{xy} = 5\);

\(\frac{x+y}{5} = XY\);

\(\frac{1}{xy} = 6\) --> XY = \(;\frac{1}{6}\);

so

\(\frac{x+y}{5} = XY = 1/6\);
GMAT Club Bot
If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ? [#permalink]
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