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If xy < 5, is x < 1 ?

(1) \(|y| > 5\)
(2) \(\frac{x}{y}> 0\)

I got the answer is C which is correct but it was a guess work. So here is how I did this question:

Statement 1

|y| > 5 i.e. y > 5 and y > -5 or y > 5 and y < -5.

As this statement doesn't say anything about x, its clearly insufficient.

Statement 2

x/y> 0 --> This statement only tells that x and y have the same sign. Therefore insufficient.

After this I struggled to complete the question, and guessed answer C as correct answer. Can someone please help?

|y| > 5 means that y<-5 or y>5.

If xy < 5, is x < 1 ?

(1) \(|y| > 5\) --> if \(y=10\) and \(x=0\) then the answer is YES but if \(y=-10\) and \(x=2\) then the answer is NO. Not sufficient.

(2) \(\frac{x}{y}>0\) --> \(x\) and \(y\) have the same sign. Still insufficient: if \(y=-2\) and \(x=-1\) then the answer is YES but if \(y=2\) and \(x=2\) then the answer is NO. Not sufficient.

(1)+(2) From (2) \(x\) and \(y\) have the same sign. Now, if from (1) \(y>5\) then \(0<x<1\) (in order \(xy<5\) to hold true) and if from (1) \(y<-5\) then \(-1<x<0\) (again in order \(xy<5\) to hold true). So in both cases \(x<1\). Sufficient.

Answer: C.

May not be the easiest solution, but I find it interesting that these inequalities can be rigorously solved using graphical visualisation.

Given : xy<5 is the area between the hyperbola.

1) |y| > 5: When y>5, x can only be less than 1. When y<-5, x can only be greater than -1. Thus not sufficient.
2) Same sign, so not sufficient.

Combining.
When y>5, x can only be less 1 BUT greater than 0. So x<1? YES
When y<-5, x can only be greater than -1 BUT less than 0. So, x<1? YES

E
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1) |y|>5
So y>5, then x<1 OR
y<-5, then x can be any value as say 10 so xy=10*-5=-50<5
Insufficient

2) x/y>0
Both X and y are of same sign
X could be 10 and y =1/3..
Or X could be -5 and y -1/2..
Insufficient

Combined
Y>5, and X>0, then x<1..
y<-5 and X<0, so X<1
Sufficient

C
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If \(xy < 5\), is \(x < 1 \)?

(1) \(|y| > 5\)
\(y < -5\) or \(y > 5\)

x could be less than or greater than 1. INSUFFICENT.

(2) \(x/y\) > 0

x and y have the same signs. Again, x could be less than or greater than 1. INSUFFICIENT.

(1&2) We know y < -5 or y >5
x must have the same sign as y.

Given xy <5, there are two scenarios:

if y > 5, x must be 0 < x < 1.
if y < -5, x must be < 1.

Sufficient.

Answer is C.
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xy < 5, x < 1?

x and y can either share the same sign or opposite signs

a) |y| > 5
Implies y > 5 or y < -5
y = 6, x = -ive
y = -6, x = +ve
Insufficient.

b) x/y > 0
implies x and y have the same sign
x = 2, y = 2 NO
x = 1/2, y = 1/2 YES
Insufficient.

Combo pack:
y = 6, x = 1/2 YES
y = -6, x = -1/2 YES
X can never be greater than 1.
Sufficient.
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