Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
21 Jun 2012, 01:55
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:30) correct
32%
(02:10)
wrong
based on 176
sessions
History
Date
Time
Result
Not Attempted Yet
21 Jun 2012, 02:07
Kudos
Bookmarks
Is x^3/y = x + x/y?
Is \(\frac{x^3}{y} = x + \frac{x}{y}\)? --> \(\frac{x^3}{y} = \frac{x(y+1)}{y}\)?
(1) y = 8. The question becomes: is \(\frac{x^3}{8} = \frac{9x}{8}\)? --> is \(x^3=9x\)? --> is \(x(x^2-9)=0\)? --> is \(x=0\), \(x=3\) or \(x=-3\)? We don't know that. Not sufficient.
(2) y = x^2 - 1. The question becomes: is \(\frac{x^3}{x^2-1} = \frac{x(x^2-1+1)}{x^2-1}\)? --> is \(\frac{x^3}{x^2-1} = \frac{x^3}{x^2-1}\)? The answer to this question is YES. Sufficient.
Answer: B.
Hope it's clear.
Is \(\frac{x^3}{y} = x + \frac{x}{y}\)? --> \(\frac{x^3}{y} = \frac{x(y+1)}{y}\)?
(1) y = 8. The question becomes: is \(\frac{x^3}{8} = \frac{9x}{8}\)? --> is \(x^3=9x\)? --> is \(x(x^2-9)=0\)? --> is \(x=0\), \(x=3\) or \(x=-3\)? We don't know that. Not sufficient.
(2) y = x^2 - 1. The question becomes: is \(\frac{x^3}{x^2-1} = \frac{x(x^2-1+1)}{x^2-1}\)? --> is \(\frac{x^3}{x^2-1} = \frac{x^3}{x^2-1}\)? The answer to this question is YES. Sufficient.
Answer: B.
Hope it's clear.
21 Jun 2012, 02:57
Kudos
Bookmarks
Thanks a lot,that really helps.I cancelled the x in A,silly mistake.
