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29 Oct 2019, 21:53
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D
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Difficulty:
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74% (00:57) correct
26%
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29 Oct 2019, 22:25
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Bunuel
If y > 0, is x less than 0?
(1) xy = 16
(2) x − y = 6
(1) xy = 16
(2) x − y = 6
(1) xy = 16
Now y>0, so x will also be positive, because product of a positive number and a negative number is negative while product of two positive numbers or two negative number is positive.
Since here product is 16>0 and y is positive , x will also be positive.
Suff
(2) x − y = 6
x=y+6... Since y>0, y+6>0 and therefore x>0
Suff
D
29 Oct 2019, 23:07
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Bunuel
If y > 0, is x less than 0?
(1) xy = 16
(2) x − y = 6
(1) xy = 16
(2) x − y = 6
Statement 1: SUFFICIENT.
"xy=POSITIVE " implies TWO issues.
(1) BOTH (x&y) POSITIVE or
(2) BOTH (x&y) NEGATIVE.
Since Y is positive, X must be positive.
Statement 2: SUFFICIENT.
X is GREATER than Y by 6 units. Since Y is positive, X must be positive.
D is my answer.
