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If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6

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Bunuel
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If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6 [#permalink] New post   29 Oct 2019, 21:53
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If y > 0, is x less than 0?

(1) xy = 16
(2) x − y = 6
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D
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chetan2u
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Re: If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6 [#permalink] New post   29 Oct 2019, 22:25
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Bunuel wrote:
If y > 0, is x less than 0?

(1) xy = 16
(2) x − y = 6



(1) xy = 16
Now y>0, so x will also be positive, because product of a positive number and a negative number is negative while product of two positive numbers or two negative number is positive.
Since here product is 16>0 and y is positive , x will also be positive.
Suff

(2) x − y = 6
x=y+6... Since y>0, y+6>0 and therefore x>0
Suff

D
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Re: If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6 [#permalink] New post   29 Oct 2019, 23:07
Bunuel wrote:
If y > 0, is x less than 0?

(1) xy = 16
(2) x − y = 6


Statement 1: SUFFICIENT.
"xy=POSITIVE " implies TWO issues.
(1) BOTH (x&y) POSITIVE or
(2) BOTH (x&y) NEGATIVE.

Since Y is positive, X must be positive.

Statement 2: SUFFICIENT.
X is GREATER than Y by 6 units. Since Y is positive, X must be positive.

D is my answer.
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Re: If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6 [#permalink] New post   29 Oct 2019, 23:13
If y > 0, is x less than 0?

y positive

(1) xy = 16 : sufficient :as statement says both x and y have same sign
(2) x − y = 6: x= y+6 : both y and 6 are positive so X has to be positive : sufficient
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Re: If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6 [#permalink] New post   30 Oct 2019, 02:19
Bunuel wrote:
If y > 0, is x less than 0?

(1) xy = 16
(2) x − y = 6


#1
xy=16
given y>0
so x has to be +ve hence >0 sufficient
#2
x-y=6
means x>y and also y>0 so x>0
sufficient
IMO D
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Re: If y > 0, is x less than 0? (1) xy = 16 (2) x − y = 6 [#permalink]
30 Oct 2019, 02:19
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Bunuel
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