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Updated on: 01 Sep 2020, 05:31
Originally posted by Jasonammex on 24 Aug 2011, 20:04.
Last edited by Bunuel on 01 Sep 2020, 05:31, edited 2 times in total.
Last edited by Bunuel on 01 Sep 2020, 05:31, edited 2 times in total.
Edited the question.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
62% (01:43) correct
38%
(01:46)
wrong
based on 301
sessions
History
Date
Time
Result
Not Attempted Yet
If \((y+3)(y-1)-(y-2)(y-1)=r(y-1)\), what is the value of y?
(1) \(r^2=25\)
(2) \(r=5\)\(\)
(1) \(r^2=25\)
(2) \(r=5\)\(\)
24 Aug 2011, 23:23
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Jasonammex
if (y+3)(y-1)-(y-2)(y-1)=r(y-1), what is the value of y?
(1) r^2=25
(2) r=5
I chose A...
(1) r^2=25
(2) r=5
I chose A...
In the equation above we see that (y-1) is the common factor in all terms. So let's take (y-1) common out of all the terms.
(y+3)(y-1) - (y-2)(y-1) - r(y-1) = 0
(y-1)[(y+3) -(y-2) - r] = 0
(y-1)(5 - r) = 0
Now, the product of these two is 0. This means that at least one of them has to be 0.
Either (y-1) = 0 or (5 - r) = 0 or both are 0.
So, either y = 1 or r = 5 or both.
Only if we know that r is not 5, then we can say that y must be 1. If r is 5, y may be 1 or may not be 1.
Stmnt 1: r^2 = 25
So r = +- 5
This statement tells us that r can be 5.
If r = 5, y may or may not be 1.
If r is not 5, y will be 1.
Since we do not know whether r is 5 or not, we cannot say what the value of y is. Not sufficient.
Stmnt 2: r = 5
If r = 5, y may or may not be 1.
Not sufficient.
Both together, r = 5. Again, not sufficient. Answer E
General Discussion
26 Aug 2011, 02:49
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Correct answer Should be B
y-1 is the common factor in the question stem
Try to break the stem as much as you can
So, y-1[(y+3) - (y-2)] = r(y-1)
= y+3-y+2 = r
r=5. So the question becomes is r=5?
Statement 1 gives us two solution + and _ 5 So insufficient
Statement 2 is sufficient because its same as our new question stem which is r=5.
Hope this helps.
y-1 is the common factor in the question stem
Try to break the stem as much as you can
So, y-1[(y+3) - (y-2)] = r(y-1)
= y+3-y+2 = r
r=5. So the question becomes is r=5?
Statement 1 gives us two solution + and _ 5 So insufficient
Statement 2 is sufficient because its same as our new question stem which is r=5.
Hope this helps.
