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overtherainbow
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) Updated on: 18 Apr 2007, 21:29
Originally posted by overtherainbow on 18 Apr 2007, 21:04.
Last edited by overtherainbow on 18 Apr 2007, 21:29, edited 3 times in total.
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If y = /x + 7/ + /2 - x/, is y = 9?
(1) x smaller than 2
(2) x greater than -7


how i did it:
critical values -7 & 2

3 regions of interest
(1) x2

working it out:

for (1)
-(x+7) -(2-x) = -9

for (2)
x+7 - (2-x) = 2x-5

for (3)
x+7+2-x =9


however when i plug numbers to test, region 3 never gives 9 :<
please let me know where my mistake is!

edit: question stem



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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 18 Apr 2007, 21:20
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overtherainbow
If y = /x + 7/ + /2 - x/, is y = 9?
(1) x <2> -7

--------------
how i did it:
critical values -7 & 2

3 regions of interest
(1) x<-7
(2) -7<x<2>2

working it out:

for (1)
-(x+7) -(2-x) = -9

for (2)
x+7 - (2-x) = 2x-5

for (3)
x+7+2-x =9


however when i plug numbers to test, region 3 never gives 9 :<
please let me know where my mistake is!
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Please provide complete question. I think something is missing here.
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 18 Apr 2007, 21:40
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overtherainbow
If y = /x + 7/ + /2 - x/, is y = 9?
(1) x smaller than 2
(2) x greater than -7


how i did it:
critical values -7 & 2

3 regions of interest
(1) x<-7
(2) -7<x<2>2

working it out:

for (1)
-(x+7) -(2-x) = -9

for (2)
x+7 - (2-x) = 2x-5

for (3)
x+7+2-x =9


however when i plug numbers to test, region 3 never gives 9 :<
please let me know where my mistake is!

edit: question stem
Show more


Answer is C
(1) if x < 2 then for x <7>= -7 it is hence INSUFF
(2) if x > -7 then for x > 7, y is not equal to 9 but for x <2 it is

Combining both we always get answer as 9

Sugegestion: For absolute value questions aways use border values.
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Juaz
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 18 Apr 2007, 22:19
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C.

y would be 9 for -7<x<2
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overtherainbow
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 18 Apr 2007, 22:24
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thx for the tip
the thing that's bugging me is i'm not sure what went wrong in my algebra
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vshaunak@gmail.com
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 19 Apr 2007, 09:24
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I believe that in order to get to check the sufficiency, plug in the values in big range.

For example:

Statement 1: x<2> -7 check for y = -6, 25

sometimes plugging in the values in smaller range can give the wrong results.
It happened to me while taking the Princeton review test. I plugged-in the values in smaller range and answered it wrong.
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 19 Apr 2007, 13:12
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overtherainbow
If y = /x + 7/ + /2 - x/, is y = 9?
(1) x smaller than 2
(2) x greater than -7


how i did it:
critical values -7 & 2

3 regions of interest
(1) x<-7
(2) -7<x<2>2

working it out:

for (1)
-(x+7) -(2-x) = -9

for (2)
x+7 - (2-x) = 2x-5

for (3)
x+7+2-x =9


however when i plug numbers to test, region 3 never gives 9 :<
please let me know where my mistake is!

edit: question stem
Show more


Both 1 and B are sufficient. Hence D.
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 20 Apr 2007, 01:24
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although the answer should be C, we do not always get y=9.

However together they answer whether y=9 yes or no definitely.

we get interval -7<x<2 so x can be any integer or fraction in that interval.
however for each such value we know the answer yes/no.
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 20 Apr 2007, 08:44
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mona_reddy78
although the answer should be C, we do not always get y=9.

However together they answer whether y=9 yes or no definitely.

we get interval -7<x<2 so x can be any integer or fraction in that interval.
however for each such value we know the answer yes/no.
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Agree we need check the value of Y and say if it is equal to 9 or not.
So stat 1( alone )and stat2 (alone) are sufficient. Why do we need both the statements.Care to explain?
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If y = /x + 7/ + /2 - x/, is y = 9? (1) x smaller than 2 (2) 20 Apr 2007, 11:14
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The answer is C.

We require both 1 and 2 to limit the application.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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