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Therefore z^2 Mod 9 = 0 ( as 9 is a factor in the same)

Answer A
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Rem (Z^2/9) = REM (6*6* A^2)/9 = REM(36*A^2)/9 = REM(0*A^2)/9

=0

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Re: If z is a multiple of 24, what is the remainder when z^2 is
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27 Jan 2014, 21:22

24 = 2^3 * 3. Any multiple of this could be 2^4 * 3, 2^3 *3^2, etc.

Let's assume z = 24 for now. So z = 2^3 * 3. Then z^2 = 2^6 * 3^2. If we divide this by 9 or 3^2 we will end up with no denominator, meaning there is no remainder.

Re: If z is a multiple of 24, what is the remainder when z^2 is
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05 Dec 2017, 07:29

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