SonGoku wrote:

If printing press A, running alone at its constant rate, produces 27,000 newspapers in six hours, how long does it take printing press B, running alone at its constant rate, to produce 27,000 newspapers?

(1) Running alone at their respective constant rates, printing press B produces two newspapers in the same amount of time that printing press A produces three newspapers.

(2) Running together at their respective constant rates, the two presses produce 7,500 newspapers in one hour.

There's basically on need of any calculation on this question.

We need to know the concept of Work =Rate*Time

Question stems tells us that the Printing Press A can produce 27k newsP in 6hrs.

We have work and time. we can calculate the rate of working. No need to calculate, its sufficient to know that we can calculate the rate.

We have to calculate the Time PrintingP takes to do same amount of work.

SO basically we need the rate of work of PrintingP B.

Statement 1: Running alone at their respective constant rates, printing press B produces two newspapers in the same amount of time that printing press A produces three newspapers.

This means that the rate of work of PrintingP B is double the rate of work of A, which we already know.

Hence, we can calculate the time taken by PrintingP B to print 27k NewsP.

Sufficient.Statement 2: Running together at their respective constant rates, the two presses produce 7,500 newspapers in one hour.

We know the individual rate of work of PrintingP A.

We are given the combined rates of work.

From this, we can calculate the rate of Work of PrintingP B. hence the time

Sufficient.Answer: DPS: There is absolutely no need to calculate the values here in this question. If you go for calculation, you are guaranteed to waste atleast 1.5 mins

Just checking the sufficiency of statements will hardly take more than 15-20 secs.

You can invest this precious time somewhere else, perhaps on a 700+ level question and attain Q51

_________________

~R.

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