NEW HERE? LEARN MORE
closeclose
Last visit was: 23 Apr 2024, 22:58 It is currently 23 Apr 2024, 22:58
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

In 1937, the ship of the great sailor SINBAD left an Egyptia

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
avatar
Asifpirlo
Manager
Manager
Joined: 10 Jul 2013
Posts: 229
Own Kudos [?]: 1036 [4]
Given Kudos: 102
Send PM
In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   15 Aug 2013, 15:03
1
Kudos
3
Bookmarks
00:00
A
B
C
D
E

Difficulty:

35% (medium)

Question Stats:

76% (02:50) correct 24% (02:57) wrong based on 109 sessions
Hide Show timer Statistics
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2
ShowHide Answer
Official Answer
A
User avatar
jaituteja
Manager
Manager
Joined: 21 Aug 2012
Posts: 82
Own Kudos [?]: 168 [1]
Given Kudos: 41
Send PM
In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   15 Aug 2013, 20:13
1
Kudos
Asifpirlo wrote:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2


A tough one initially.. Took me around 3 minutes to solve..
But it is logic based.. No rocket science quant required...

The answer should be A...

WEST ( Sindbad after 6 months at Xmiles/month) -------------------------------------
Egyptian Port
|
|
|
(5000 miles) |
|
|
|
|
 
CHENG I SAO ship ay Y miles/ month (SOUTH)


Now, since CHENG's ship started one month after that of Sindabad.

So, when Sindabad travels for 6 months,i.e he travels 6X distance, CHENG would travel for 5 months, i.e 5Y distance

Now, when CHENG travels for 5 months, he covers some distance of 5000, so the distance from the orgin/Egyptian Port will be (5000-5Y).

CHENG will be 6X to west and Sindabad will be 5000-5Y to south.

Applying pythagorus theorum,

the distance b/w them will be { (6x)^2 + (5000-5y)^2 }^1/2



I have a doubt, what if 5y exceeds 5000...???????

Thanks,
Jai
 
User avatar
blueseas
Current Student
Joined: 14 Dec 2012
Posts: 580
Own Kudos [?]: 4324 [2]
Given Kudos: 197
Location: India
Concentration: General Management, Operations
Schools: PGDM (GM) '15 (A)
GMAT 1: 700 Q50 V34
GPA: 3.6
Send PM
GMAT ToolKit User
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   16 Aug 2013, 00:47
2
Kudos
Asifpirlo wrote:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2


distance travelled by sindabad in 6 months =\(6X\)
as pirates started 1 month late==>distance travelled by pirates in 5 month =\(5Y\)

See diag we need to calculate distance WT
WT =\(\sqrt{(5000-5Y)^2+(6X)^2}\)...(USING PYTHAGORAS THEOREM)

hence A.
Attachments

PIRATES.png
PIRATES.png [ 17.83 KiB | Viewed 3081 times ]

avatar
Asifpirlo
Manager
Manager
Joined: 10 Jul 2013
Posts: 229
Own Kudos [?]: 1036 [3]
Given Kudos: 102
Send PM
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   16 Aug 2013, 04:08
2
Kudos
1
Bookmarks
Asifpirlo wrote:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2

Nice try friends. Right you are.
here is my solution :
Attachments

ship math.png
ship math.png [ 27.16 KiB | Viewed 3056 times ]

avatar
Asifpirlo
Manager
Manager
Joined: 10 Jul 2013
Posts: 229
Own Kudos [?]: 1036 [1]
Given Kudos: 102
Send PM
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   Updated on: 17 Aug 2013, 03:59
1
Kudos
jaituteja wrote:
Asifpirlo wrote:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2


A tough one initially.. Took me around 3 minutes to solve..
But it is logic based.. No rocket science quant required...

The answer should be A...

WEST ( Sindbad after 6 months at Xmiles/month) -------------------------------------
Egyptian Port
|
|
|
(5000 miles) |
|
|
|
|

CHENG I SAO ship ay Y miles/ month (SOUTH)


Now, since CHENG's ship started one month after that of Sindabad.

So, when Sindabad travels for 6 months,i.e he travels 6X distance, CHENG would travel for 5 months, i.e 5Y distance

Now, when CHENG travels for 5 months, he covers some distance of 5000, so the distance from the orgin/Egyptian Port will be (5000-5Y).

CHENG will be 6X to west and Sindabad will be 5000-5Y to south.

Applying pythagorus theorum,

the distance b/w them will be { (6x)^2 + (5000-5y)^2 }^1/2



I have a doubt, what if 5y exceeds 5000...???????

Thanks,
Jai

Please give KUDOS if it helped..!!!! :)



Special Thanks to you for properly citing about this problem. This may seem impossible but it is just the simple one indeed..... Thanks jai...

solution of the doubt :
the distance b/w them will be { (6x)^2 +(5000-5y)^2 }^1/2
I have a doubt, what if 5y exceeds 5000...???????
yes it could be, but no problem at all. because (a-b)^2 = (b-a)^2

they are inside whole square..... You will have the same value no matter who is greater..............

Originally posted by Asifpirlo on 16 Aug 2013, 15:01.
Last edited by Asifpirlo on 17 Aug 2013, 03:59, edited 1 time in total.
avatar
SandyNik
Intern
Intern
Joined: 12 Jun 2014
Posts: 2
Own Kudos [?]: 1 [0]
Given Kudos: 162
Schools: Ross '16 INSEAD Jan '15 Tuck '16 Kellogg 1YR '15 Sloan '16 Booth ISB '15 NUS '16 Duke Fuqua Stern '16
Send PM
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   04 Jan 2015, 09:28
@Asifpirlo...Ans is A.....and I am saying so based on the following logic:-
The chinese ship sailed for 5 months i.e. 5Y miles @Y miles/month, therefore distance from Egyptian port is 5000-5Y. Since A is the only option with this value ...therefore A is the answer
User avatar
B
Lodz697
Intern
Intern
Joined: 11 Oct 2023
Posts: 46
Own Kudos [?]: 11 [0]
Given Kudos: 96
Location: Italy
Concentration: Finance, Entrepreneurship
GPA: 3.77
Send PM
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   29 Feb 2024, 03:55
How do we know that the trajectories of the boats are perpendicular?
User avatar
B
Gmatguy007
Manager
Manager
Joined: 07 Feb 2024
Posts: 71
Own Kudos [?]: 5 [0]
Given Kudos: 93
Send PM
In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   29 Feb 2024, 05:31
 
jaituteja wrote:
Asifpirlo wrote:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2

A tough one initially.. Took me around 3 minutes to solve..
But it is logic based.. No rocket science quant required...

The answer should be A...

WEST ( Sindbad after 6 months at Xmiles/month) -------------------------------------


Egyptian Port

|
|
|
(5000 miles) |
|
|
|
|

CHENG I SAO ship ay Y miles/ month (SOUTH)


Now, since CHENG's ship started one month after that of Sindabad.

So, when Sindabad travels for 6 months,i.e he travels 6X distance, CHENG would travel for 5 months, i.e 5Y distance

Now, when CHENG travels for 5 months, he covers some distance of 5000, so the distance from the orgin/Egyptian Port will be (5000-5Y).

CHENG will be 6X to west and Sindabad will be 5000-5Y to south.

Applying pythagorus theorum,

the distance b/w them will be { (6x)^2 + (5000-5y)^2 }^1/2



I have a doubt, what if 5y exceeds 5000...???????

Thanks,
Jai

Please give KUDOS if it helped..!!!! :)


 

­Hey jaituteja !

Your answer is indeed such a helpful method but I'd like to help me understand a specific part. In the highlighted text, why the distance and direction of each boat switched? (CHENG has 5.000 - 5Y distance and is located south and accordingly Sindbad is west with 6X distance).­

Could anyone chip in? JeffTargetTestPrep KarishmaB manasp35
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14816
Own Kudos [?]: 64887 [0]
Given Kudos: 426
Location: Pune, India
Send PM
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   17 Apr 2024, 22:52
Expert Reply
Gmatguy007 wrote:
jaituteja wrote:
Asifpirlo wrote:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at X mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]

(A) { (6x)^2 + (5000-5y)^2 }^1/2
(B) { (36x)^2 + (5000-7y)^2 }^1/2
(C) { (16x)^2 + (5000-7y)^2 }^1/2
(D) { (7x)^2 + (5200-7y)^2 }^1/2
(E) { (2x)^2 + (300-7y)^2 }^1/2

A tough one initially.. Took me around 3 minutes to solve..
But it is logic based.. No rocket science quant required...

The answer should be A...

WEST ( Sindbad after 6 months at Xmiles/month) -------------------------------------



Egyptian Port

|
|
|
(5000 miles) |
|
|
|
|

CHENG I SAO ship ay Y miles/ month (SOUTH)


Now, since CHENG's ship started one month after that of Sindabad.

So, when Sindabad travels for 6 months,i.e he travels 6X distance, CHENG would travel for 5 months, i.e 5Y distance

Now, when CHENG travels for 5 months, he covers some distance of 5000, so the distance from the orgin/Egyptian Port will be (5000-5Y).

CHENG will be 6X to west and Sindabad will be 5000-5Y to south.

Applying pythagorus theorum,

the distance b/w them will be { (6x)^2 + (5000-5y)^2 }^1/2



I have a doubt, what if 5y exceeds 5000...???????

Thanks,
Jai

Please give KUDOS if it helped..!!!! :)



 

­Hey jaituteja !

Your answer is indeed such a helpful method but I'd like to help me understand a specific part. In the highlighted text, why the distance and direction of each boat switched? (CHENG has 5.000 - 5Y distance and is located south and accordingly Sindbad is west with 6X distance).­

Could anyone chip in? JeffTargetTestPrep KarishmaB manasp35

­

Nothing switched. Jaituteja just reversed the names mistakenly while writing that. 
User avatar
B
Gmatguy007
Manager
Manager
Joined: 07 Feb 2024
Posts: 71
Own Kudos [?]: 5 [0]
Given Kudos: 93
Send PM
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink] New post   18 Apr 2024, 08:28
KarishmaB wrote:
Gmatguy007 wrote:
­Hey jaituteja !

Your answer is indeed such a helpful method but I'd like to help me understand a specific part. In the highlighted text, why the distance and direction of each boat switched? (CHENG has 5.000 - 5Y distance and is located south and accordingly Sindbad is west with 6X distance).­

Could anyone chip in? JeffTargetTestPrep KarishmaB manasp35

Nothing switched. Jaituteja just reversed the names mistakenly while writing that. 

­That's what I thought at first, but I wanted to be sure that i didn't miss something.
GMAT Club Bot
gmatclubot
Re: In 1937, the ship of the great sailor SINBAD left an Egyptia [#permalink]
18 Apr 2024, 08:28
Moderators:
Bunuel
Math Expert
92883 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions