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Updated on: 07 Sep 2025, 09:41
Originally posted by jananijayakumar on 20 Aug 2010, 01:58.
Last edited by Bunuel on 07 Sep 2025, 09:41, edited 1 time in total.
Last edited by Bunuel on 07 Sep 2025, 09:41, edited 1 time in total.
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C
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In 1995 Division A of company had 4850 customers. If there were 86 service errors in Division A that year, what was service-error rate, in number of service errors per 100 customers, for Division B of Company X in 1995?
(1) In 1995 the overall service-error rate for Division A and B combined was 1.5 errors per 100 customers.
(2) In 1995 Division B had 9,350 customers, none of whom were customers of Division A
Untitled.jpg [ 139.63 KiB | Viewed 18870 times ]
(1) In 1995 the overall service-error rate for Division A and B combined was 1.5 errors per 100 customers.
(2) In 1995 Division B had 9,350 customers, none of whom were customers of Division A
Attachment:
Untitled.jpg [ 139.63 KiB | Viewed 18870 times ]
In 1995 Division A of the company had 4850 customers, If there were 86 servise errors in Division A that year, what was servise error rate, in number of servise errors per 100 customers in Division B of the company in 1995?
Question \(\frac{x}{B}100=?\) Where x is the servise errors in Division B and B is # of customers of division B.
(1) In 1995 the overall service error rate for Division A and B combined was 1,5 errors per 100 customers.
\(\frac{86+x}{4850+B}=\frac{1.5}{100}\), two variables one equation - cannot solve for variables. Also can not get the ratio needed. Not sufficient.
(2) IN 1995 division B had 9350 customers, non of whom were customers for division A
B=9350, clearly insufficient.
(1)+(2) We know the value of B, hence we can calculate x, from (1) and the fraction \(\frac{x}{B}\). Sufficient.
Answer: C.
Question \(\frac{x}{B}100=?\) Where x is the servise errors in Division B and B is # of customers of division B.
(1) In 1995 the overall service error rate for Division A and B combined was 1,5 errors per 100 customers.
\(\frac{86+x}{4850+B}=\frac{1.5}{100}\), two variables one equation - cannot solve for variables. Also can not get the ratio needed. Not sufficient.
(2) IN 1995 division B had 9350 customers, non of whom were customers for division A
B=9350, clearly insufficient.
(1)+(2) We know the value of B, hence we can calculate x, from (1) and the fraction \(\frac{x}{B}\). Sufficient.
Answer: C.
General Discussion
17 Nov 2010, 08:24
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Rephrase the question:
Is there sufficient info to know the ratio of errors to customers in division B, if the error ratio for division A is already known?
Statement 1: The Ratio for the two divisions combined is insufficient, because I don't know how much customer overlap there is.
Statement 2: The number of customers in Division B is insufficient because I don't know how many errors there are.
However statement 2 adds that there is no customer overlap, so if I combine the two statements there is sufficient info.
The answer is C
Is there sufficient info to know the ratio of errors to customers in division B, if the error ratio for division A is already known?
Statement 1: The Ratio for the two divisions combined is insufficient, because I don't know how much customer overlap there is.
Statement 2: The number of customers in Division B is insufficient because I don't know how many errors there are.
However statement 2 adds that there is no customer overlap, so if I combine the two statements there is sufficient info.
The answer is C
