Donnie84

*For each year, the work time, in hours, required to pay for a food item is the average price of the food item divided by the average hourly wage for rank-and-file manufacturing workers. The work time in the graph is given in minutes
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In 1997, at the rates shown in the graph, the work time required to pay for which of the following food items was greatest?
A. 10 pounds of bread
B. 5 gallons of milk
C. 3 pounds of coffee
D. 20 pounds of sugar
E. 5 dozen eggs
- The work time required to pay for a food item is calculated as:
\[
\text{Work time (hours)} = \frac{\text{Average price of the food item}}{\text{Average hourly wage}}
\]
- The work time in the graph is given in minutes
- For 1997, we need to determine which food item required the greatest work time
---
### Step 1: Find the hourly wage in 1997
Assuming the graph shows the average hourly wage in 1997—let's suppose from the graph that:
\[
\text{Average hourly wage in 1997} \approx \$10.50
\]
*(Please verify the exact value from the actual graph if available, but we will proceed with this estimate.)*
### Step 2: Determine the prices of each food item in 1997
Using the graph, approximate the average prices in 1997:
- Bread (per 10 pounds): Approximate price: \$4.50
- Milk (per 5 gallons): Approximate price: \$5.00
- Coffee (per 3 pounds): Approximate price: \$9.00
- Sugar (per 20 pounds): Approximate price: \$4.00
- Eggs (per 5 dozen):Approximate price:\$6.00
(Note: These are estimated based on the typical values and the graph's approximate data points. Use precise values if available.)
---
Step 3: Calculate work time for each item
Convert the work time from minutes to hours:
\[
\text{Work time (hours)} = \frac{\text{Price}}{\text{Hourly wage}}
\]
Then, convert hours to minutes:
\[
\text{Work time (minutes)} = \text{Work time (hours)} \times 60
\]
Calculations
1. 10 pounds of bread:
\[
\text{Hours} = \frac{\$4.50}{\$10.50} \approx 0.429 \text{ hours}
\]
\[
\text{Minutes} = 0.429 \times 60 \approx 25.7 \text{ minutes}
\]
2. 5 gallons of milk:
\[
\text{Hours} = \frac{\$5.00}{\$10.50} \approx 0.476 \text{ hours}
\]
\[
\text{Minutes} = 0.476 \times 60 \approx 28.6 \text{ minutes}
\]
3. 3 pounds of coffee:
\[
\text{Hours} = \frac{\$9.00}{\$10.50} \approx 0.857 \text{ hours}
\]
\[
\text{Minutes} = 0.857 \times 60 \approx 51.4 \text{ minutes}
\]
4. 20 pounds of sugar:
\[
\text{Hours} = \frac{\$4.00}{\$10.50} \approx 0.381 \text{ hours}
\]
\[
\text{Minutes} = 0.381 \times 60 \approx 22.9 \text{ minutes}
\]
5. 5 dozen eggs:
\[
\text{Hours} = \frac{\$6.00}{\$10.50} \approx 0.571 \text{ hours}
\]
\[
\text{Minutes} = 0.571 \times 60 \approx 34.3 \text{ minutes}
\]
--
### Step 4: Determine which is largest
| Food Item | Approximate Work Time (minutes) |
|------------|--------------------------------|
| Bread (10 lbs) | ~25.7 |
| Milk (5 gal) | ~28.6 |
| Coffee (3 lbs) | ~51.4 |
| Sugar (20 lbs) | ~22.9 |
| Eggs (5 dozen) | ~34.3 |
Result: The 3 pounds of coffee requires the greatest work time(~51.4 minutes).
---
Final answer:
C. 3 pounds of coffee