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In 2003 Acme Computer priced its computers five times higher

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In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 16 Apr 2008, 20:48
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In 2003 Acme Computer priced its computers five times higher than its printers. What is the ratio of its gross revenue for computers and printers respectively in the year 2003?

(1) In the first half of 2003 it sold computers and printers in the ratio of 3:2, respectively, and in the second half in the ratio of 2:1.

(2) It sold each computer for $1000.
[Reveal] Spoiler: OA
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Re: In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 16 Apr 2008, 21:17
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Let say each printer cost p, then computer will cost 5p.

Statement 1:
Suppose 5x equipments were sold in first half, then computer = 3x and printer = 2x.
Similarly Suppose 3y equipments were sold in first half, then computer = 2y and printer = y.
Total computers sold = 3x + 2y
Total printers sold = 2x + y
Ratio = (3x+2y)*5p/(2x+y)*p = (3x+2y)*5/(2x+y), we need x and y to get the value so this statement alone is insufficient.

Statement 2:
Just tells us 5p = 1000 => p = 200
But nothing about how many of each equipment sold, so alone insufficient.

Combining both is not going to help either, as you can see from 1 that we need x, and y (not the value of p, that cancels out anyway).

Answer E.
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Re: In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 17 Apr 2008, 04:48
E for me. We need to know 2 things: the price for each item, and the number of each item sold. Thats the only way we can calculate revenues for both.

So, from stat 1, we have some info on ratios, but nothing about price. Insuff.

From stat 2, we can get the price of both items, but theres no inform on quantity sold. Insuff.

Together, it looks like we have enough info, but we realize that the quantity is only given in terms of a ratio. So, theres no way to find out how many of computers and printers were actually sold. Together, insuff.
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Re: In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 17 Apr 2008, 09:34
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moni77 wrote:
In 2003 Acme Computer priced its computers five times higher than its printers. What is the ratio of its gross revenue for computers and printers respectively in the year 2003?

(1) In the first half of 2003 it sold computers and printers in the ratio of 3:2, respectively, and in the second half in the ratio of 2:1.

(2) It sold each computer for $1000.


E.

C = Price of computer
P = price of printer
Nc = Number of computer sold
Np = Number of printer sold

Given
C=5P

Ratio of Gross Revenue = (C * Nc)/(P * Np) = 5*(Nc/Np)
(1) Not enough information. We cannot find total ratio using half a year ratio information.
INSUFFICIENT

(2) Totally irrelevant
INSUFFICIENT

Together, same...INSUFFICIENT
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Re: In 2003 Acme Computer priced its computers five times higher [#permalink]

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moni77 wrote:
In 2003 Acme Computer priced its computers five times higher than its printers. What is the ratio of its gross revenue for computers and printers respectively in the year 2003?

(1) In the first half of 2003 it sold computers and printers in the ratio of 3:2, respectively, and in the second half in the ratio of 2:1.

(2) It sold each computer for $1000.




c- price of computer
p- price of printer.

given c= 5p

Gross revenue - no of product * price.


1. first half : c:p --> 3.2 i.e 3x:2x where x is no of product sold. say if x=1 then for every 2 printer , 3 computers. and cycle goes on.
second half : c:p --> 2:1 i.e 2y:y same logic which applied for x.

applying the gross revenue formula...

to find the ratio for computer : printer is

(3x+2y) 5p : (2x+y) p

cancelling p -> (3x+2y) : (2x+y) --> since we know only the ratio & does know no of products hence Not suff.

2. Given price of computer is 1000 then printer is 200 but does know the no of products sold.

Hence Not suff.

1+2 --> still we are not sure exact no of products sold.

Hence E.
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Re: In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 18 Feb 2016, 08:47
Pc = 5Pp
Rc/Rp = 5Pp*C/Pp*P <=> 5C/P =?
1) First half 2003: 3C1 = 2P1 , Second half 2003: 2C2 = P2
Not sufficient.
2) Pc = 1000$ Not sufficient
1) & 2) still not sufficient <=> Answer E.
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In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 13 Apr 2018, 23:38
Bunuel niks18 amanvermagmat chetan2u

Quote:
]In 2003 Acme Computer priced its computers five times higher than its printers. What is the ratio of its gross revenue for computers and printers respectively in the year 2003?

(1) In the first half of 2003 it sold computers and printers in the ratio of 3:2, respectively, and in the second half in the ratio of 2:1.

(2) It sold each computer for $1000.


What is incorrect in below approach?

pc: price of computer
pp: price of printer
x: no of computers sold
y: no of printers sold

Q: pcx + ppy = ?
Given : pc= 5pp
St 1:
x/y = 3/2 In first half of year
x/y = 2/1 In second half of year

Two distinct eqs will give me x and y.
p: unknown. Insuff


St 2:
pc= 5pp = 1000

x and y: unknown.

Combining: we get all values of pc, pp,x and y.

Can you suggest if highlighted part is correct?
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Re: In 2003 Acme Computer priced its computers five times higher [#permalink]

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New post 14 Apr 2018, 11:18
adkikani wrote:
Bunuel niks18 amanvermagmat chetan2u

Quote:
]In 2003 Acme Computer priced its computers five times higher than its printers. What is the ratio of its gross revenue for computers and printers respectively in the year 2003?

(1) In the first half of 2003 it sold computers and printers in the ratio of 3:2, respectively, and in the second half in the ratio of 2:1.

(2) It sold each computer for $1000.


What is incorrect in below approach?

pc: price of computer
pp: price of printer
x: no of computers sold
y: no of printers sold

Q: pcx + ppy = ?
Given : pc= 5pp
St 1:
x/y = 3/2 In first half of year
x/y = 2/1 In second half of year

Two distinct eqs will give me x and y.
p: unknown. Insuff


St 2:
pc= 5pp = 1000

x and y: unknown.

Combining: we get all values of pc, pp,x and y.

Can you suggest if highlighted part is correct?


Hello

You have done: x/y = 3/2 in first half of the year
and x/y = 2/1 in second half of the year

Well first mistake is to assume that no of computers and printers sold will be x & y respectively for both halves of the year. We dont know whether the ratios of computers to printers sold will be same, so we CANNOT take these ratios for both halves of the year to be x/y only.

Secondly, you have done x/y = 3/2 and then immediately x/y = 2/1. How can x/y give two different values??

So basically, going by your method, what we can do is this: Assume ratio is x/y in first half and p/q in second half. So we have x/y = 3/2 and p/q = 2/1
Re: In 2003 Acme Computer priced its computers five times higher   [#permalink] 14 Apr 2018, 11:18
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