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# In a acertain company, the ratio of the numer of manager to

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Intern
Joined: 26 May 2010
Posts: 32
Location: International
Schools: Stern, Chicago, Duke, UNC, Wharton
WE 1: S&T
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In a acertain company, the ratio of the numer of manager to [#permalink]

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20 Sep 2010, 19:40
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86% (02:08) correct 14% (02:08) wrong based on 235 sessions

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In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25
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Joined: 02 Sep 2010
Posts: 775
Location: London
Re: Ratio PS Manager Production line worker [#permalink]

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20 Sep 2010, 19:44
3
1
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25

Let there be x managers. Then the number of workers is 72/5 * x
With extra workers the ratio becomes 5 to 74, therefore :

$$\frac{(72/5)x + 8}{x}=\frac{74}{5}$$

$$72x + 40 = 74x$$

$$x = 20$$

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Joined: 02 Sep 2009
Posts: 47015
Re: Ratio PS Manager Production line worker [#permalink]

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20 Sep 2010, 21:30
2
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25

You can solve this problem the way discussed above or try the following:

Given: $$\frac{m}{w}=\frac{5x}{72x}$$, now 8 workers were hired and new ratio became $$\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}$$, notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

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Intern
Joined: 26 May 2010
Posts: 32
Location: International
Schools: Stern, Chicago, Duke, UNC, Wharton
WE 1: S&T
WE 2: Project Management
WE 3: Banking
Re: Ratio PS Manager Production line worker [#permalink]

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21 Sep 2010, 06:08
Intern
Joined: 05 Jan 2012
Posts: 1
Concentration: Finance, Accounting
GMAT Date: 05-15-2012
GPA: 3.53
WE: Accounting (Manufacturing)

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05 Feb 2012, 01:24
1
let manager=m , and worker =w
m/w=5/72
=5w=72m.....1
m/w+8=5/74
5w+40=74m...........2
by solving the equations.....we find m=20
so ans is D
Manager
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Posts: 146
Location: India
WE: Information Technology (Investment Banking)
Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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05 Feb 2012, 03:22
Ans is D
m/w = 5/72 and m/w+8 = 5/74
where m is no of managers and w is the no of production workers. On solving we get the answer as m=20
Director
Joined: 02 Sep 2016
Posts: 742
Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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20 Aug 2017, 00:20
Bunuel wrote:
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25

You can solve this problem the way discussed above or try the following:

Given: $$\frac{m}{w}=\frac{5x}{72x}$$, now 8 workers were hired and new ratio became $$\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}$$, notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Hello Bunuel

Do we have to keep the constant x same even when we get new ratio ?
Manager
Joined: 30 May 2012
Posts: 211
Location: United States (TX)
Concentration: Finance, Marketing
GPA: 3.3
WE: Information Technology (Consulting)
Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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01 Sep 2017, 06:33
Yes, the 'x' will be the same. It is just the ratio that changes.
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Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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07 Sep 2017, 07:09
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25

We are given that the ratio of managers to production-line workers is 5 to 72, or 5x to 72x. We can create the following equation:

(5x)/(72x + 8) = 5/74

74(5x) = (72x + 8)(5)

370x = 360x + 40

10x = 40

x = 4

The company has 4 x 5 = 20 managers.

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Posts: 649
Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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02 Mar 2018, 04:49
Bunuel wrote:
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25

You can solve this problem the way discussed above or try the following:

Given: $$\frac{m}{w}=\frac{5x}{72x}$$, now 8 workers were hired and new ratio became $$\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}$$, notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Hi Bunuel

can please explain whats wrong with my solution and why

let manager be $$y$$

let line worker production be $$x$$

$$\frac{5y}{72x+4}$$ =$$\frac{5y}{74x}$$ cross multiply

$$360xy+20y=370xy$$

$$20y=370xy-360xy$$

$$20y=10xy$$
Intern
Joined: 01 Aug 2017
Posts: 9
Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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09 Mar 2018, 12:02
1
dave13 wrote:
Bunuel wrote:
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25

You can solve this problem the way discussed above or try the following:

Given: $$\frac{m}{w}=\frac{5x}{72x}$$, now 8 workers were hired and new ratio became $$\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}$$, notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Hi Bunuel

can please explain whats wrong with my solution and why

let manager be $$y$$

let line worker production be $$x$$

$$\frac{5y}{72x+4}$$ =$$\frac{5y}{74x}$$ cross multiply

$$360xy+20y=370xy$$

$$20y=370xy-360xy$$

$$20y=10xy$$

It's because you are saying that the ratio is not 5 to 74. You are saying that managers are y and workers are x, you can say that but when you go to solve the problem you are saying that the ratios are 5y:74x thus the resolution is not correct.

Hope it's clear!
Re: In a acertain company, the ratio of the numer of manager to   [#permalink] 09 Mar 2018, 12:02
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