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In a acertain company, the ratio of the numer of manager to [#permalink]
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20 Sep 2010, 19:40
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In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have? A. 5 B. 10 C. 15 D. 20 E. 25
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Re: Ratio PS Manager Production line worker [#permalink]
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20 Sep 2010, 19:44
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Gacarva wrote: In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have?
A. 5 B. 10 C. 15 D. 20 E. 25 Let there be x managers. Then the number of workers is 72/5 * x With extra workers the ratio becomes 5 to 74, therefore : \(\frac{(72/5)x + 8}{x}=\frac{74}{5}\) \(72x + 40 = 74x\) \(x = 20\) Answer is (d)
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Re: Ratio PS Manager Production line worker [#permalink]
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20 Sep 2010, 21:30
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Gacarva wrote: In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have?
A. 5 B. 10 C. 15 D. 20 E. 25 You can solve this problem the way discussed above or try the following: Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 > x=4), so 5 parts in nominator correspond to 5*4=20 managers. Answer: D.
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Re: Ratio PS Manager Production line worker [#permalink]
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21 Sep 2010, 06:08
Thank you all, I will work on problems like this one and follow your advice.



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let manager=m , and worker =w m/w=5/72 =5w=72m.....1 m/w+8=5/74 5w+40=74m...........2 by solving the equations.....we find m=20 so ans is D



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Re: In a acertain company, the ratio of the numer of manager to [#permalink]
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05 Feb 2012, 03:22
Ans is D m/w = 5/72 and m/w+8 = 5/74 where m is no of managers and w is the no of production workers. On solving we get the answer as m=20



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Re: In a acertain company, the ratio of the numer of manager to [#permalink]
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20 Aug 2017, 00:20
Bunuel wrote: Gacarva wrote: In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have?
A. 5 B. 10 C. 15 D. 20 E. 25 You can solve this problem the way discussed above or try the following: Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 > x=4), so 5 parts in nominator correspond to 5*4=20 managers. Answer: D. Hello BunuelDo we have to keep the constant x same even when we get new ratio ?



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Re: In a acertain company, the ratio of the numer of manager to [#permalink]
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01 Sep 2017, 06:33
Yes, the 'x' will be the same. It is just the ratio that changes.



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Re: In a acertain company, the ratio of the numer of manager to [#permalink]
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07 Sep 2017, 07:09
Gacarva wrote: In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have?
A. 5 B. 10 C. 15 D. 20 E. 25 We are given that the ratio of managers to productionline workers is 5 to 72, or 5x to 72x. We can create the following equation: (5x)/(72x + 8) = 5/74 74(5x) = (72x + 8)(5) 370x = 360x + 40 10x = 40 x = 4 The company has 4 x 5 = 20 managers. Answer: D
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Re: In a acertain company, the ratio of the numer of manager to [#permalink]
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02 Mar 2018, 04:49
Bunuel wrote: Gacarva wrote: In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have?
A. 5 B. 10 C. 15 D. 20 E. 25 You can solve this problem the way discussed above or try the following: Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 > x=4), so 5 parts in nominator correspond to 5*4=20 managers. Answer: D. Hi Bunuel can please explain whats wrong with my solution and why let manager be \(y\) let line worker production be \(x\) \(\frac{5y}{72x+4}\) =\(\frac{5y}{74x}\) cross multiply \(360xy+20y=370xy\) \(20y=370xy360xy\) \(20y=10xy\)



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Re: In a acertain company, the ratio of the numer of manager to [#permalink]
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09 Mar 2018, 12:02
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dave13 wrote: Bunuel wrote: Gacarva wrote: In a acertain company, the ratio of the numer of manager to the number of productionline workers is 5 to 72. If 8 additional Productionline workers were to be hired, the ratio of the number of managers to the number of productionline workers would be 5 to 74. How many managers does the company have?
A. 5 B. 10 C. 15 D. 20 E. 25 You can solve this problem the way discussed above or try the following: Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 > x=4), so 5 parts in nominator correspond to 5*4=20 managers. Answer: D. Hi Bunuel can please explain whats wrong with my solution and why let manager be \(y\) let line worker production be \(x\) \(\frac{5y}{72x+4}\) =\(\frac{5y}{74x}\) cross multiply \(360xy+20y=370xy\) \(20y=370xy360xy\) \(20y=10xy\) It's because you are saying that the ratio is not 5 to 74. You are saying that managers are y and workers are x, you can say that but when you go to solve the problem you are saying that the ratios are 5y:74x thus the resolution is not correct. Hope it's clear!




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