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In a acertain company, the ratio of the numer of manager to

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In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 20 Sep 2010, 18:40
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In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25
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Re: Ratio PS Manager Production line worker  [#permalink]

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New post 20 Sep 2010, 18:44
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2
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


Let there be x managers. Then the number of workers is 72/5 * x
With extra workers the ratio becomes 5 to 74, therefore :

\(\frac{(72/5)x + 8}{x}=\frac{74}{5}\)

\(72x + 40 = 74x\)

\(x = 20\)

Answer is (d)
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Re: Ratio PS Manager Production line worker  [#permalink]

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New post 20 Sep 2010, 20:30
2
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


You can solve this problem the way discussed above or try the following:

Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Answer: D.
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Re: Ratio PS Manager Production line worker  [#permalink]

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New post 21 Sep 2010, 05:08
Thank you all, I will work on problems like this one and follow your advice.
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company  [#permalink]

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New post 05 Feb 2012, 00:24
1
let manager=m , and worker =w
m/w=5/72
=5w=72m.....1
m/w+8=5/74
5w+40=74m...........2
by solving the equations.....we find m=20
so ans is D
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 05 Feb 2012, 02:22
Ans is D
m/w = 5/72 and m/w+8 = 5/74
where m is no of managers and w is the no of production workers. On solving we get the answer as m=20
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 19 Aug 2017, 23:20
Bunuel wrote:
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


You can solve this problem the way discussed above or try the following:

Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Answer: D.



Hello Bunuel

Do we have to keep the constant x same even when we get new ratio ?
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 01 Sep 2017, 05:33
Yes, the 'x' will be the same. It is just the ratio that changes.
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 07 Sep 2017, 06:09
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


We are given that the ratio of managers to production-line workers is 5 to 72, or 5x to 72x. We can create the following equation:

(5x)/(72x + 8) = 5/74

74(5x) = (72x + 8)(5)

370x = 360x + 40

10x = 40

x = 4

The company has 4 x 5 = 20 managers.

Answer: D
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 02 Mar 2018, 03:49
Bunuel wrote:
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


You can solve this problem the way discussed above or try the following:

Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Answer: D.


Hi Bunuel :-)

can please explain whats wrong with my solution and why :?

let manager be \(y\)

let line worker production be \(x\)

\(\frac{5y}{72x+4}\) =\(\frac{5y}{74x}\) cross multiply

\(360xy+20y=370xy\)

\(20y=370xy-360xy\)

\(20y=10xy\)
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 09 Mar 2018, 11:02
1
dave13 wrote:
Bunuel wrote:
Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


You can solve this problem the way discussed above or try the following:

Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Answer: D.


Hi Bunuel :-)

can please explain whats wrong with my solution and why :?

let manager be \(y\)

let line worker production be \(x\)

\(\frac{5y}{72x+4}\) =\(\frac{5y}{74x}\) cross multiply

\(360xy+20y=370xy\)

\(20y=370xy-360xy\)

\(20y=10xy\)



It's because you are saying that the ratio is not 5 to 74. You are saying that managers are y and workers are x, you can say that but when you go to solve the problem you are saying that the ratios are 5y:74x thus the resolution is not correct.

Hope it's clear!
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Re: In a acertain company, the ratio of the numer of manager to  [#permalink]

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New post 27 Aug 2018, 04:22
Gacarva wrote:
In a certain company, the ratio of the number of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


OA:D
Let initially number of manager be \(5x\) and number of workers be \(72x\).

\(\frac{5x}{72x+8}=\frac{5}{74}\)

\(74x=72x+8\)

\(2x=8\quad;\quad x=4\)

Number of manager \(=5x =5*4 =20\)
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Re: In a acertain company, the ratio of the numer of manager to &nbs [#permalink] 27 Aug 2018, 04:22
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