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In a certain class of students, 25% received A’s on the fina

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In a certain class of students, 25% received A’s on the fina [#permalink]

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In a certain class of students, 25% received A’s on the final exam and 2/3 of these students received A’s in the class as a whole. If 15 students in the class received A’s on the final exam but did not receive an A in the class, how many students did not receive an A on the final exam?

A. 45
B. 60
C. 105
D. 135
E. 180
[Reveal] Spoiler: OA

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Re: In a certain class of students [#permalink]

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New post 22 May 2013, 12:43
This question has a complicated text, lets try to semplify it.

25% received A’s on the final exam and 2/3 of these students received A’s in the class as a whole

\(25%\) A in final => \(25%*\frac{2}{3}\)=overall A - \(25%*\frac{1}{3}\)=No overall A

If 15 students in the class received A’s on the final exam but did not receive an A in the class

Now this portion refers to the expression \(25%*\frac{1}{3}\) (A in final but no overall) so \(25%*\frac{1}{3}=15\)

With that expression we know that 25%*1/3 of the students equals 15. so 25% of the students are 25%*(1/3)*3=15*3

\(25%=15*3=45\)

Number of students=\(180\)

how many students did not receive an A on the final exam? (25% received A’s)

\(180*\frac{3}{4}=135\) or even better \(180-45=135\)

D
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Re: In a certain class of students [#permalink]

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pikachu wrote:
In a certain class of students, 25% received A’s on the final exam and 2/3 of these students received A’s in the class as a whole. If 15 students in the class received A’s on the final exam but did not receive an A in the class, how many students did not receive an A on the final exam?
A. 45
B. 60
C. 105
D. 135
E. 180


Finally after hammering through the confusing text and spending a ton of time :cry: I was able to figure out an easy way to solve this problem by using the matrix approach. Lets set up a matrix as in the attachment:

Since the problem involves a fraction 2/3 and a percent 25%, the best way to move forward is to convert the 25% into a fraction = 1/4. Note the denominator of the two fractions would be 1/3*1/4 = 1/12. So let the total number of students in the class be 12x. Hence the number of students who got an A on the final exam would be 3x (as we are told that 25% of the total population received an A on the final exam). We also know that the number of students who did get an A on the final exam but did not get an A in the class = 15 = x. So we can simply use this knowledge to calculate 9x = 15*9 = 135. Answer D.
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Re: In a certain class of students [#permalink]

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pikachu wrote:
In a certain class of students, 25% received A’s on the final exam and 2/3 of these students received A’s in the class as a whole. If 15 students in the class received A’s on the final exam but did not receive an A in the class, how many students did not receive an A on the final exam?
A. 45
B. 60
C. 105
D. 135
E. 180


Let the total no of students in the class be S. Now, S/4 = 'A' on final exam--> 2/3rd = S/6 = Received A's in the class.Thus, students who received A's only on the final exam = 1/3*S/4 = S/12--> S/12 = 15 or S = 180. Thus, Students not receiving A on the final exam = 3/4*S = 45*3 = 135.

D.

One can also eliminate options B,C immediately after reading the question.
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Re: In a certain class of students [#permalink]

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New post 23 May 2013, 07:22
vinaymimani wrote:
pikachu wrote:
In a certain class of students, 25% received A’s on the final exam and 2/3 of these students received A’s in the class as a whole. If 15 students in the class received A’s on the final exam but did not receive an A in the class, how many students did not receive an A on the final exam?
A. 45
B. 60
C. 105
D. 135
E. 180


Let the total no of students in the class be S. Now, S/4 = 'A' on final exam--> 2/3rd = S/6 = Received A's in the class.Thus, students who received A's only on the final exam = 1/3*S/4 = S/12--> S/12 = 15 or S = 180. Thus, Students not receiving A on the final exam = 3/4*S = 45*3 = 135.

D.

One can also eliminate options B,C immediately after reading the question.


Hi vinaymimani,

"One can also eliminate options B,C immediately after reading the question" can you please elaborate how. This is one thing I struggle with is eliminating the wrong answer choices. Any suggestions.
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Re: In a certain class of students [#permalink]

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New post 23 May 2013, 08:34
pikachu wrote:
vinaymimani wrote:
pikachu wrote:
In a certain class of students, 25% received A’s on the final exam and 2/3 of these students received A’s in the class as a whole. If 15 students in the class received A’s on the final exam but did not receive an A in the class, how many students did not receive an A on the final exam?
A. 45
B. 60
C. 105
D. 135
E. 180

One can also eliminate options B,C immediately after reading the question.


Hi vinaymimani,

"One can also eliminate options B,C immediately after reading the question" can you please elaborate how. This is one thing I struggle with is eliminating the wrong answer choices. Any suggestions.


Sure. We know that 25% received A on the final exam. Thus, those who didn't receive A on the final exam = 75% = 3/4*S, where S is the no of students in the class.
Thus, S/4 = 25% of S = The no of people who received A on the final exam = one of the options/3 = Options/3. Now, again, 2/3rd of THESE many students received A in the calss as whole --> 2*option/9 = Integer. Options B and C are not divisible by 9. The remaining three are. Hope this clears your doubt.
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Re: In a certain class of students, 25% received A’s on the fina [#permalink]

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New post 26 Jul 2014, 20:51
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Re: In a certain class of students, 25% received A’s on the fina [#permalink]

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New post 18 Feb 2016, 02:28
Hello from the GMAT Club BumpBot!

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Re: In a certain class of students, 25% received A’s on the fina [#permalink]

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Here's another way to do using double-matrix method:
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In a certain class of students, 25% received A’s on the fina [#permalink]

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New post 23 Jul 2016, 17:04
\(Answer\; =\; \frac{75*45}{25}\; =\; 135\;\)

\(15\; =>\; \frac{1}{3},\; \frac{3}{3}\; =\; 45,\)

\(45=\; 25\)% \(\; of \; total\)

\(100-25=\; 75\)

\(45:25=x:75\)

\(\frac{75*45}{25}\; =\; 135\)

\(Answer\; D\;\)
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Re: In a certain class of students, 25% received A’s on the fina [#permalink]

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New post 20 Mar 2017, 14:50
try to write what is asked in the beginning, that's why I failed this question

I tried grid as presented above and got to the point 15=1/12
question asks what is 3/4 or 9/12=>15*9=135
Re: In a certain class of students, 25% received A’s on the fina   [#permalink] 20 Mar 2017, 14:50
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