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Bunuel
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In a certain party, every person drinks either tea or coffee. If 60% drink tea and 70% drink coffee, what is the probability that a person drinking tea also drinks coffee?


Drinks Tea~Drinks TeaTotal
Drinks Coffee30%40%70%
~Drinks Coffee30%0%30%
Total60%40%100%

The probability that a person drinking tea also drinks coffee = 30%/60% = 1/2

IMO A
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i d9nr understand the probabilty done in the end it doesnt make sense ro me30/60 why
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i d9nr understand the probabilty done in the end it doesnt make sense ro me30/60 why
Conditional probability P(A/B) = \(\frac{P(A ∩ B)}{P(B)}\) ie. probability of event A such that event B occurs

Here, P(Coffee/Tea) = \(\frac{P({Coffee ∩ Tea})}{P(Tea)}\), where,

P(Coffee ∩ Tea) = 30/100 = 3/10
P(Tea) = 60/100 = 6/10

which means, P(Coffee/Tea) = \(\frac{3/10}{6/10}\) = \(\frac{1}{2}\)

Answer : A
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