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In a certain shipment, x out of every y items were found to be defecti

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In a certain shipment, x out of every y items were found to be defecti  [#permalink]

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New post 18 Feb 2018, 21:53
1
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00:00
A
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D
E

Difficulty:

  55% (hard)

Question Stats:

61% (01:41) correct 39% (01:31) wrong based on 70 sessions

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In a certain shipment, x out of every y items were found to be defective. If 10 defective items were found in the shipment, what was the total number of items in the shipment?

(A) 10y/x
(B) 10x/y
(C) 10y
(D) 10y/(y - x)
(E) 10y/(x - y)

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In a certain shipment, x out of every y items were found to be defecti  [#permalink]

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New post Updated on: 18 Feb 2018, 23:01
1
X defective items come out of Y items
1............................................\(\frac{Y}{X}\) items

10...........................................\(\frac{Y}{X}\)*10 items

= \(\frac{10Y}{X}\)

Answer: A.
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Originally posted by varun4s on 18 Feb 2018, 22:03.
Last edited by varun4s on 18 Feb 2018, 23:01, edited 1 time in total.
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Re: In a certain shipment, x out of every y items were found to be defecti  [#permalink]

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New post 18 Feb 2018, 22:59
x defective items in Y..
1 defective item in Y/X
10 in 10Y/X

Hence A


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Re: In a certain shipment, x out of every y items were found to be defecti  [#permalink]

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New post 19 Feb 2018, 14:07
1
Bunuel wrote:
In a certain shipment, x out of every y items were found to be defective. If 10 defective items were found in the shipment, what was the total number of items in the shipment?

(A) 10y/x
(B) 10x/y
(C) 10y
(D) 10y/(y - x)
(E) 10y/(x - y)


Let x = 10 in every y=100.....Total shipment = 100

Check choices

(A) 10y/x = 10 (100)/10 = 100........Keep
(B) 10x/y = 10 (10)/100 = 1............Eliminate
(C) 10y =1000............Eliminate
(D) 10y/(y - x) =10 (100) / 90 ............Eliminate
(E) 10y/(x - y) ............Eliminate

Answer: A
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Re: In a certain shipment, x out of every y items were found to be defecti  [#permalink]

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New post 21 Feb 2018, 13:26
Bunuel wrote:
In a certain shipment, x out of every y items were found to be defective. If 10 defective items were found in the shipment, what was the total number of items in the shipment?

(A) 10y/x
(B) 10x/y
(C) 10y
(D) 10y/(y - x)
(E) 10y/(x - y)


We can create the following proportion, where n is the total number of items in the shipment:

x/y = 10/n

xn = 10y

n = 10y/x

Answer: A
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Re: In a certain shipment, x out of every y items were found to be defecti &nbs [#permalink] 21 Feb 2018, 13:26
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