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In a certain state, gasoline stations compute the price per

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In a certain state, gasoline stations compute the price per  [#permalink]

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New post Updated on: 10 Dec 2013, 05:28
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In a certain state, gasoline stations compute the price per gallon "p", in dollars, charged at the pump by adding a 4 percent sales tax to the dealer's price per gallon "d", in dollars, and then adding a gasoline tax of $0.18 per gallon. Which of the following gives the dealer's price per gallon "d" in terms of the price per gallon "p" charged at the pump?

A. d=p-0.22
B. d=p/1.22
C. d=p/1.04 - 0.18
D. d= p-0.18/1.04
E. d = p-0.04/1.18

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-certain-state-gasoline-stations-compute-the-price-per-100598.html#p776714

Originally posted by jimmyjamesdonkey on 15 Apr 2008, 14:21.
Last edited by Bunuel on 10 Dec 2013, 05:28, edited 1 time in total.
Edited the question and added the OA.
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Re: GMATPrep PS: Can you solve it fast somehow?  [#permalink]

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New post 15 Apr 2008, 14:29
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p = d*1.04 + 18 (Based on the question. 4% Sales Tax +0.18 cents per gallon)

Rearranging,

d = (p-0.18)/1.04

Answer is D
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Re: GMATPrep PS: Can you solve it fast somehow?  [#permalink]

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New post 10 Dec 2013, 05:24
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yellowjacket wrote:
p = d*1.04 + 18 (Based on the question. 4% Sales Tax +0.18 cents per gallon)

Rearranging,

d = (p-0.18)/1.04

Answer is D




How is the bolded part even true? Doesn't the question really say: p/gallon = d*1.04 + 18/gallon

Thus, how can you "remove" the fractions p/gallon and 1/gallon from both sides without multiplying gallon with d*1.04? What am I missing?

Because I easily understand the question when it is done as you say, but logically I just cannot seem to understand WHY the fraction /gallon is not included in your equation.
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Re: GMATPrep PS: Can you solve it fast somehow?  [#permalink]

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New post 10 Dec 2013, 05:28
aeglorre wrote:
yellowjacket wrote:
p = d*1.04 + 18 (Based on the question. 4% Sales Tax +0.18 cents per gallon)

Rearranging,

d = (p-0.18)/1.04

Answer is D




How is the bolded part even true? Doesn't the question really say: p/gallon = d*1.04 + 18/gallon

Thus, how can you "remove" the fractions p/gallon and 1/gallon from both sides without multiplying gallon with d*1.04? What am I missing?

Because I easily understand the question when it is done as you say, but logically I just cannot seem to understand WHY the fraction /gallon is not included in your equation.


In a certain state, gasoline stations compute the price per gallon "p", in dollars, charged at the pump by adding a 4 percent sales tax to the dealer's price per gallon "d", in dollars, and then adding a gasoline tax of $0.18 per gallon. Which of the following gives the dealer's price per gallon "d" in terms of the price per gallon "p" charged at the pump?

A. d=p-0.22
B. d=p/1.22
C. d=p/1.04 - 0.18
D. d= p-0.18/1.04
E. d = p-0.04/1.18

Price per gallon \(p\) equals to \(d+0.04d\) (dealer's price \(d\) plus 4%) plus \(0.18\), so \(p=d+0.04d+0.18\) --> \(p=1.04d+0.18\) --> \(d=\frac{p-0.18}{1.04}\).

Answer: D.

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-certain-state-gasoline-stations-compute-the-price-per-100598.html#p776714
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Re: In a certain state, gasoline stations compute the price per  [#permalink]

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New post 14 Aug 2018, 22:34
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