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15 Feb 2024, 10:44
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In a certain variety of poker, known as Draw Loss Poker, each possible poker card combination has a raw point value. The following table shows the raw point values for the card combinations themselves.
one pair = 12 points
two pair = 36 points
three of a kind = 60 points
straight = 300 points
flush = 540 points
full house = 720 points
four of a kind = 3,600 points
straight flush = 60,000 points
Explanation of the card combinations. A straight is a sequence of five consecutive valued cards (e.g. 8, 9 10, Jack, Queen) of any suits. A flush is a set of five cards of the same suit. A full house is three-of-a-kind of one value of card and a pair of another value of card (e.g. three 7's and two aces). A straight flush is a sequence of five consecutive valued cards all of the same suit.
If one's final card combination does not include any of these special combinations, the hand is worth zero points.
one pair = 12 points
two pair = 36 points
three of a kind = 60 points
straight = 300 points
flush = 540 points
full house = 720 points
four of a kind = 3,600 points
straight flush = 60,000 points
Explanation of the card combinations. A straight is a sequence of five consecutive valued cards (e.g. 8, 9 10, Jack, Queen) of any suits. A flush is a set of five cards of the same suit. A full house is three-of-a-kind of one value of card and a pair of another value of card (e.g. three 7's and two aces). A straight flush is a sequence of five consecutive valued cards all of the same suit.
If one's final card combination does not include any of these special combinations, the hand is worth zero points.
Three-of-a-kind: Player A outscores
Player B Full House: Player A does not
outscores Player B Four-of-a-kind: Player A does not
outscores Player B
Player B Full House: Player A does not
outscores Player B Four-of-a-kind: Player A does not
outscores Player B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
76% (03:13) correct
24%
(02:25)
wrong
based on 1372
sessions
History
Date
Time
Result
Not Attempted Yet
1. Player A initially draws three-of-a-kind and chooses not to discard at all on the discard round. Player B initially draws three-of-a-kind, discards the remaining two cards. For the following final card combinations of Player B, tell whether Player A outscores Player B.
|
Player A outscores Player B |
Player A does not outscores Player B |
|
| Three-of-a-kind | ||
| Full House | ||
| Four-of-a-kind |
ShowHide Answer
Official Answer
Three-of-a-kind: Player A outscores
Player B Full House: Player A does not
outscores Player B Four-of-a-kind: Player A does not
outscores Player B
Player B Full House: Player A does not
outscores Player B Four-of-a-kind: Player A does not
outscores Player B
discard 2 cards, straight
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
77% (01:51) correct
23%
(01:52)
wrong
based on 1295
sessions
History
Date
Time
Result
Not Attempted Yet
2. Suppose player J draws two pair and chooses not to discard any cards. Suppose player K draws three-of-a-kind and choose not to discard any cards. Which of the following discard choices and final card combination would have a higher point value than player J’s hand but not than player K’s hand?
| discard 1 card, three of a kind | |
| discard 2 cards, flush | |
| discard 2 cards, straight | |
| discard 3 cards, full house | |
| discard 4 cards, full house |
ShowHide Answer
Official Answer
discard 2 cards, straight
598
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
58% (02:28) correct
42%
(02:14)
wrong
based on 1128
sessions
History
Date
Time
Result
Not Attempted Yet
3. Player G received the following cards on the initial five-card draw: 2 of Clubs, 5 of Diamonds, 8 of Hearts, 8 of Spades, and King of Diamonds. Player G will choose to discard exactly two cards, the 2 of Clubs and 5 of Diamonds. Over all possible hands that could result, what is the range of the possible point values of Player G’s final hand?
| 588 | |
| 598 | |
| 1794 | |
| 3588 | |
| 3598 |
discard 4 of Diamonds & 7 of Clubs, winds up with a flush: Player T does not
outscores player S discard 6 of Hearts, winds up with a full house: Player T outscores
player S discards 4 of Diamonds & 4 of Hearts & 6 of Hearts, winds up with four-of-a-kind: Player T outscores
player S
outscores player S discard 6 of Hearts, winds up with a full house: Player T outscores
player S discards 4 of Diamonds & 4 of Hearts & 6 of Hearts, winds up with four-of-a-kind: Player T outscores
player S
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (01:53) correct
24%
(01:23)
wrong
based on 1101
sessions
History
Date
Time
Result
Not Attempted Yet
4. Suppose player S draws a straight on the first five-card draw and choose not to discard any cards. Player T initially draws the following five cards: 4 of Diamonds, 4 of Hearts, 6 of Hearts, 7 of Hearts, 7 of Clubs. Which of Player T’s discard choices and final results will outscore Player S?
|
Player T outscores player S |
Player T does not outscores player S |
|
| discard 4 of Diamonds & 7 of Clubs, winds up with a flush | ||
| discard 6 of Hearts, winds up with a full house | ||
| discards 4 of Diamonds & 4 of Hearts & 6 of Hearts, winds up with four-of-a-kind |
ShowHide Answer
Official Answer
discard 4 of Diamonds & 7 of Clubs, winds up with a flush: Player T does not
outscores player S discard 6 of Hearts, winds up with a full house: Player T outscores
player S discards 4 of Diamonds & 4 of Hearts & 6 of Hearts, winds up with four-of-a-kind: Player T outscores
player S
outscores player S discard 6 of Hearts, winds up with a full house: Player T outscores
player S discards 4 of Diamonds & 4 of Hearts & 6 of Hearts, winds up with four-of-a-kind: Player T outscores
player S
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21 Mar 2024, 11:38
Kudos
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Official Explanation
1. Player A initially draws three-of-a-kind and chooses not to discard at all on the discard round. Player B initially draws three-of-a-kind, discards the remaining two cards. For the following final card combinations of Player B, tell whether Player A outscores Player B.
Explanation
Player A draw three-of-a-kind (worth 60 points), and does not discard, so A’s hand is worth 60 points. In all three cases, B discards two cards, for a reducing factor of 1/6.
(a) B’s final hand = three-of-a-kind, which is (60)*(1/6) = 10 points. A outscores B.
(b) B’s final hand = Full House, which is (720)*(1/6) = 120 points. A does not outscore B.
(c) B’s final hand = Four-of-a-kind, which is (3600)*(1/6) = 600 points. A does not outscore B.
It wasn’t relevant in any of these scenarios, but notice the exact wording — if A and B were tied, the answer would be “A does not outscore B."
Explanation
Player A draw three-of-a-kind (worth 60 points), and does not discard, so A’s hand is worth 60 points. In all three cases, B discards two cards, for a reducing factor of 1/6.
(a) B’s final hand = three-of-a-kind, which is (60)*(1/6) = 10 points. A outscores B.
(b) B’s final hand = Full House, which is (720)*(1/6) = 120 points. A does not outscore B.
(c) B’s final hand = Four-of-a-kind, which is (3600)*(1/6) = 600 points. A does not outscore B.
It wasn’t relevant in any of these scenarios, but notice the exact wording — if A and B were tied, the answer would be “A does not outscore B."
21 Mar 2024, 11:43
Kudos
Bookmarks
Official Explanation
2. Suppose player J draws two pair and chooses not to discard any cards. Suppose player K draws three-of-a-kind and choose not to discard any cards. Which of the following discard choices and final card combination would have a higher point value than player J’s hand but not than player K’s hand?
Explanation
Player J, with two pair and no discards, has 36 points. Player K, with three-of-a-kind and no discards, has 60 points. We want a combination worth more than 30 points but less than 60 points.
(A) discard 1 card, three of a kind = (60)*(1/2) = 30. Less than 36, no good.
(B) discard 2 cards, flush = (540)*(1/6) = 90. Higher than 60, no good.
(C) discard 2 cards, straight = (300)*(1/6) = 50. This could work.
(D) discard 3 cards, full house = (720)*(1/10) = 72. Higher than 60, no good.
(E) discard 4 cards, full house = (720)*(1/60) = 12. Less than 36, no good.
(C) is the only hand & discard combination that is in the required range.
Explanation
Player J, with two pair and no discards, has 36 points. Player K, with three-of-a-kind and no discards, has 60 points. We want a combination worth more than 30 points but less than 60 points.
(A) discard 1 card, three of a kind = (60)*(1/2) = 30. Less than 36, no good.
(B) discard 2 cards, flush = (540)*(1/6) = 90. Higher than 60, no good.
(C) discard 2 cards, straight = (300)*(1/6) = 50. This could work.
(D) discard 3 cards, full house = (720)*(1/10) = 72. Higher than 60, no good.
(E) discard 4 cards, full house = (720)*(1/60) = 12. Less than 36, no good.
(C) is the only hand & discard combination that is in the required range.
