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In a certain year, Minnesota produced 2/3 and Michigan produced 1/6 of

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In a certain year, Minnesota produced 2/3 and Michigan produced 1/6 of  [#permalink]

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New post 08 Jan 2019, 22:56
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Question Stats:

80% (01:34) correct 20% (01:54) wrong based on 15 sessions

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In a certain year, Minnesota produced \(\frac{2}{3}\) and Michigan produced \(\frac{1}{6}\) of all the iron ore produced in the United States. If all the other states combined produced 18 million tons that year, how many million tons did Minnesota produce that year?


(A) 27

(B) 36

(C) 54

(D) 72

(E) 162

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In a certain year, Minnesota produced 2/3 and Michigan produced 1/6 of  [#permalink]

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New post 08 Jan 2019, 23:03
Bunuel wrote:
In a certain year, Minnesota produced \(\frac{2}{3}\) and Michigan produced \(\frac{1}{6}\) of all the iron ore produced in the United States. If all the other states combined produced 18 million tons that year, how many million tons did Minnesota produce that year?


(A) 27

(B) 36

(C) 54

(D) 72

(E) 162


OA is D

2/3rd+1/6th = 5/6th so 1/6th was produces by the rest of the states. So 18x6x2/3 is what Minnesota produces.
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Re: In a certain year, Minnesota produced 2/3 and Michigan produced 1/6 of  [#permalink]

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New post 09 Jan 2019, 01:13
Bunuel wrote:
In a certain year, Minnesota produced \(\frac{2}{3}\) and Michigan produced \(\frac{1}{6}\) of all the iron ore produced in the United States. If all the other states combined produced 18 million tons that year, how many million tons did Minnesota produce that year?


(A) 27

(B) 36

(C) 54

(D) 72

(E) 162



total producted 2/3 +1/6 = 5/6
or say 1/6th producing states = 18
x = 18*6 = 108
108 * 2/3 = 72 IMO D
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Re: In a certain year, Minnesota produced 2/3 and Michigan produced 1/6 of &nbs [#permalink] 09 Jan 2019, 01:13
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In a certain year, Minnesota produced 2/3 and Michigan produced 1/6 of

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