|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
21 Jan 2025, 03:00
Kudos
Bookmarks
Maximum: 7
Minimum: 4
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
53% (02:16) correct
47%
(01:51)
wrong
based on 299
sessions
History
Date
Time
Result
Not Attempted Yet
In a class of 30 students, each student reads exactly one newspaper, with no more than nine students reading the same newspaper. Furthermore, each newspaper is read by a different number of students.
Select for Maximum the highest possible number of newspapers that could have been read by the class, and select for Minimum the lowest possible number of newspapers that could have been read by the class. Make only two selections, one in each column.
Select for Maximum the highest possible number of newspapers that could have been read by the class, and select for Minimum the lowest possible number of newspapers that could have been read by the class. Make only two selections, one in each column.
| Maximum | Minimum | |
| 3 | ||
| 4 | ||
| 6 | ||
| 7 | ||
| 8 | ||
| 30 |
ShowHide Answer
Official Answer
Maximum: 7
Minimum: 4
29 Jan 2025, 10:00
Kudos
Bookmarks
Bunuel
Official Solution:
To maximize the number of different newspapers read by the class, we need to minimize the number of students reading each newspaper. Let 1 student read one newspaper, 2 students read another, 3 students read a third newspaper, and so on. This gives the sum: \(1 + 2 + 3 + 4 + 5 + 6 + 7 + ...\). Adding these, we see that 7 newspapers would account for a total of 28 students. We cannot exceed 7 newspapers because doing so would require more than 30 students. However, we can adjust the total from 28 to 30 by increasing the last group, reading the seventh kind of newspaper, from 7 students to 9 students. Thus, the distribution becomes \(1 + 2 + 3 + 4 + 5 + 6 + 9 = 30\). Therefore, the maximum number of newspapers that could have been read by the class is 7.
To minimize the number of different newspapers read by the class, we need to maximize the number of students reading each newspaper. Since no more than nine students can read the same newspaper, the first group of 9 students could read one newspaper, the next group of 8 could read another, the third group of 7 could read a third newspaper, and the fourth group of 6 could read a fourth newspaper. Adding these groups gives us \(9 + 8 + 7 + 6 = 30\). Therefore, the minimum number of newspapers that could have been read by the class is 4.
Correct answer:
Maximum "7"
Minimum "4"
Attachment:
GMAT-Club-Forum-cv5ju23h.png [ 8.32 KiB | Viewed 1950 times ]
General Discussion
