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In a field day at a school, each child who competed in n events and sc [#permalink]

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23 Jul 2017, 10:16

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In a field day at a school, each child who competed in \(n\) events and scored a total of \(p\) points was given an overall score of \(\frac{p}{n} + n\). Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

Re: In a field day at a school, each child who competed in n events and sc [#permalink]

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23 Jul 2017, 18:01

carcass wrote:

In a field day at a school, each child who competed in n events and scored a total of p points was given an overall score of P/n + n. n Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

A. \(\frac{10}{23}\)

B.\(\frac{7}{10}\)

C. \(\frac{4}{5}\)

D.\(\frac{10}{9}\)

E. \(\frac{12}{7}\)

It should be D

For readers, denominator for P is just 1 n. The fraction then adds into so you can rewrite it as \(n + \frac{p}{n}\) for a clearer understanding.

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In a field day at a school, each child who competed in \(n\) events and scored a total of \(p\) points was given an overall score of \(\frac{p}{n} + n\). Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

A. \(\frac{10}{23}\)

B. \(\frac{7}{10}\)

C. \(\frac{4}{5}\)

D. \(\frac{10}{9}\)

E. \(\frac{12}{7}\)

Since Andrew competed in 1 event and received 9 points, his overall score was:

9/1 + 1 = 10

Since Jason completed in 3 events and scored 5, 6, and 7 points, he scored a total of 18 points and his overall score was:

18/3 + 3 = 9

Thus, the ratio of Andrew’s score to Jason’s score is 10/9.

Answer: D
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