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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
72% (02:39) correct
28%
(02:48)
wrong
based on 176
sessions
History
Date
Time
Result
Not Attempted Yet
In a group 30% of the men are more than 25 years old and 80% of the men are less than or equal to 50 years old. Twenty percent of all men play football. If 20% of the men above the age of 50 play football, what % of the players are less than or equal to 50 years ?
A. 50
B. 60
C. 75
D. 80
E. 85
A. 50
B. 60
C. 75
D. 80
E. 85
16 Nov 2019, 19:18
Kudos
Bookmarks
KSBGC
Of course the question is faulty the way it is. It should be 30% and not 305 and 20% and not 205 as I believe instead of %, 5 has been written..
'30% of the men are more than 25 years old' is redundant information and can be discarded.
So we take total strength to be 100..
80 % or \(80\leq{50}\) yrs, so \(20>50\) yrs....
Now 20% of total play football, so 20 play football. Also 20% of >50yrs play football, that is 20% of 20 play football.
Thus, 20-4=16 players are less than or equal to 50 yrs..
% of the players are less than or equal to 50 years means 16 is what % of 20 = 100*16/20=80%.
OA given is also incorrect.
16 Nov 2019, 23:27
Kudos
Bookmarks
KSBGC
The highlighted part means that 20% of men who are above 50 play football.
Thus if total men are 100 then 20 are above 50. Hence 20% of 20 = \(\frac{20}{100} * 20\) = 4 men above 50 play football.
20% of total men means = \(\frac{20}{100} * 100 \)= 20 men play football.
So, 20 - 4 = 16 men under or equal to 50 play football.
\(\frac{16}{20} * 100\) = 80%
Answer D.
