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Bunuel
In a hair cut competition, the number of blonde girls is three times bigger than the number of brown haired girls, and the number of brown haired girls is twice the number of red haired girls. Assuming that there is no other hair color, what is the proportion of the brown haired girls?

A. 2/3.
B. 4/9.
C. 1/3.
D. 5/9.
E. 2/9.
Let, No of Red haired Girl be = 1 , So, Brown haired Girls = 2 and No of blonde girls = 6 , Total No of Girls = 9

So, proportion of the brown haired girls is 2/9 , Answer must be (E)
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Bunuel
In a hair cut competition, the number of blonde girls is three times bigger than the number of brown haired girls, and the number of brown haired girls is twice the number of red haired girls. Assuming that there is no other hair color, what is the proportion of the brown haired girls?

A. 2/3.
B. 4/9.
C. 1/3.
D. 5/9.
E. 2/9.

We can let D = the number of blonde girls, W = the number of brown haired girls, and R = the number of red haired girls. We can create the equations:

D = 3W

and

W = 2R

W/2 = R

The proportion of brown haired girls is:

W/(W + 3W + W/2)

Multiplying by 2/2, we have:

2W/(2W + 6W + W) = 2W/9W = 2/9

Answer: E
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3 times bigger than brown hair is it not 4 times Abhishek009

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In a hair cut competition, the number of blonde girls is three times bigger than the number of brown haired girls, and the number of brown haired girls is twice the number of red haired girls. Assuming that there is no other hair color, what is the proportion of the brown haired girls?

the number of blonde girls is three times bigger than the number of brown haired girls
=> \(Blonde=4*Brown\)

the number of brown haired girls is twice the number of red haired girls
=> \(Brown=2*Red\)

what is the proportion of the brown haired girls?
=> \(\frac{Brown}{Brown+Blonde+Red}\)

=> \(\frac{Brown}{Brown+4*Brown+0.5*Brown}\)

OA has the first statement mis-translated.
=> \(\frac{1}{5.5}=\frac{2}{11}\)
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