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15 Oct 2019, 02:25
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
64% (01:17) correct
36%
(00:55)
wrong
based on 186
sessions
History
Date
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Not Attempted Yet
In a hotel with single rooms and double rooms, what is the probability that a room chosen at random will be a double room painted red?
(1) 1/6 of the rooms in the hotel are painted red.
(2) 2/3 of the hotel's rooms are double rooms.
(1) 1/6 of the rooms in the hotel are painted red.
(2) 2/3 of the hotel's rooms are double rooms.
16 Oct 2019, 14:23
Kudos
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Let 18 be the total number of Single and Double rooms in a hotel
—> (just a multiplication of 3 and 6)
\(\frac{Red_{double}}{18}\) ???
(Statement1): (1/6)*18 = 3 ( total red rooms in a hotel, not just red double rooms)
Insufficient
(Statement2): (2/3)*18= 12 double rooms.
—> No info about how many red double rooms are.
Insufficient
Taken together 1&2, still tells us nothing about double rooms painted red.
Insufficient
The answer is E.
Posted from my mobile device
—> (just a multiplication of 3 and 6)
\(\frac{Red_{double}}{18}\) ???
(Statement1): (1/6)*18 = 3 ( total red rooms in a hotel, not just red double rooms)
Insufficient
(Statement2): (2/3)*18= 12 double rooms.
—> No info about how many red double rooms are.
Insufficient
Taken together 1&2, still tells us nothing about double rooms painted red.
Insufficient
The answer is E.
Posted from my mobile device
29 Oct 2019, 00:51
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Bunuel
Here is my approach:
I assumed total rooms to be 120 and made a table similar to the one attached.
Since none of the statements give a correlation between single and double rooms that are red or single and double rooms that are not red..we cannot find the answer with either of the statements. Hence E is the answer.
Attachments
Picture2.png [ 66.01 KiB | Viewed 3456 times ]
