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03 Aug 2023, 05:44
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No. of people answering "yes" to question 1 = N/4
No. of people answering "yes" to questions 1 & 2 = (1/3)*(N/4)=N/12
No. of people who didn’t answer "yes" to questions 1 & 2 = N – N/12 =11N/12
Hence E
No. of people answering "yes" to questions 1 & 2 = (1/3)*(N/4)=N/12
No. of people who didn’t answer "yes" to questions 1 & 2 = N – N/12 =11N/12
Hence E
02 Oct 2023, 09:15
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sudzpwc
The question is based on simple percentages.
1/4 of N answered "yes" to question 1. Of those (which means of 1/4th of N), 1/3 answered "yes" to question 2. So those who answered Yes to both questions are simply 1/3rd of (1/4)th of N = (1/3)*(1/4)N = (1/12)N
This means that the other (11/12)N did not answer "Yes" to both questions. Some of them could have answered "Yes" to either one question but they did not answer "Yes" to both.
Hence answer is 11N/12.
Answer (E)
Check this video on Percentages: https://youtu.be/HxnsYI1Rws8
02 Oct 2023, 10:30
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sudzpwc
\(Let , N = 12 (LCM of 3 & 4)\)
\(Q1_y = 3\) ; \(Q1_n = 9\)
\(Q2_y = 1\) ; \(Q2_n = 2\)
So, \(Q1_n + Q2N = 9 + 2 = 11\)
Quote:
= \(11\) Or, \(\frac{11*12}{12}\), Answer must be (E)
