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# In a park, there are owners accompanied with atleast one pet dog. Tota

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Math Expert
Joined: 02 Sep 2009
Posts: 51162
In a park, there are owners accompanied with atleast one pet dog. Tota  [#permalink]

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01 Aug 2018, 23:11
00:00

Difficulty:

15% (low)

Question Stats:

87% (01:21) correct 13% (00:44) wrong based on 30 sessions

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In a park, there are owners accompanied with atleast one pet dog. Total head count of dogs & owners is 90 and there total leg count is 270. How many owners & dogs are there in the park?

A. 21 Owners, 69 Dogs

B. 30 Owners, 60 Dogs

C. 33 Owners, 54 Dogs

D. 39 Owners, 51 Dogs

E. 45 Owners, 45 Dogs

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In a park, there are owners accompanied with atleast one pet dog. Tota  [#permalink]

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01 Aug 2018, 23:26
Ans: E
given D + O = 90
and 2O+4D =270 from these equations we can find D= 45 and O =45

We can also work this from Options: Option C is out as head count is =87 wrong
Leg count options A= 42+276 =318 wrong
Option B: 60+240 =300 (wrong)
Option D: 78+201 =279 wrong
Option E: 90+180 =270 (correct)

Bunuel wrote:
In a park, there are owners accompanied with atleast one pet dog. Total head count of dogs & owners is 90 and there total leg count is 270. How many owners & dogs are there in the park?

A. 21 Owners, 69 Dogs

B. 30 Owners, 60 Dogs

C. 33 Owners, 54 Dogs

D. 39 Owners, 51 Dogs

E. 45 Owners, 45 Dogs

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Posts: 665
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Re: In a park, there are owners accompanied with atleast one pet dog. Tota  [#permalink]

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02 Aug 2018, 02:18
Bunuel wrote:
In a park, there are owners accompanied with atleast one pet dog. Total head count of dogs & owners is 90 and there total leg count is 270. How many owners & dogs are there in the park?

D + O = 90
O = 90 - D -- 1)

2O + 4D = 270
O + 2D = 135 -- 2)

On solving, we get
90 - D + 2D = 135
D = 45, and O = 45

Hence, E.
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Re: In a park, there are owners accompanied with atleast one pet dog. Tota &nbs [#permalink] 02 Aug 2018, 02:18
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