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# In a race of 4800 meters run on a circular track of 400 meters length,

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Math Expert
Joined: 02 Sep 2009
Posts: 64314
In a race of 4800 meters run on a circular track of 400 meters length,  [#permalink]

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10 Jan 2020, 03:02
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Difficulty:

85% (hard)

Question Stats:

28% (02:15) correct 72% (02:20) wrong based on 29 sessions

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In a race of 4800 meters run on a circular track of 400 meters length, the ratio of the speed of the two athletes is 3 : 5. If they run in the opposite directions, how many times do they meet in the entire race?

A. 11
B. 13
C. 15
D. 17
E. 19

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Math Expert
Joined: 02 Sep 2009
Posts: 64314
Re: In a race of 4800 meters run on a circular track of 400 meters length,  [#permalink]

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10 Jan 2020, 03:03
Bunuel wrote:
In a race of 4800 meters run on a circular track of 400 meters length, the ratio of the speed of the two athletes is 3 : 5. If they run in the opposite directions, how many times do they meet in the entire race?

A. 11
B. 13
C. 15
D. 17
E. 19

TWIN QUESTION: https://gmatclub.com/forum/in-a-race-of ... 13872.html
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Joined: 27 May 2012
Posts: 1045
Re: In a race of 4800 meters run on a circular track of 400 meters length,  [#permalink]

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22 Jan 2020, 11:33
Bunuel wrote:
In a race of 4800 meters run on a circular track of 400 meters length, the ratio of the speed of the two athletes is 3 : 5. If they run in the opposite directions, how many times do they meet in the entire race?

A. 11
B. 13
C. 15
D. 17
E. 19

Let A's speed be 5 and B's speed be 3 since they are moving in opposite directions, relative speed 5+3=8
Relative speed= 8 , so first time they meet $$\frac{400}{8}$$ = 50 seconds.
In 50 Seconds A moves 250 m
or in every 250 meters A will meet B once .
Hence in 4800 meters A will meet B $$\frac{4800}{250}= 19.2$$ times or 19 times.
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- Stne
Re: In a race of 4800 meters run on a circular track of 400 meters length,   [#permalink] 22 Jan 2020, 11:33