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AJB77
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In a survey, 20% favored candidate A, 30% favored candidate 02 Jul 2005, 07:55
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In a survey, 20% favored candidate A, 30% favored candidate B and 50% favored candidate C. Exactly 5% favored all candidates

What percentage of voters favored atleast two candidates?

S1. 80% of those asked were in favor of atleast one of the candidates A, B and C

S2. 17% of those asked favored both Candidate A and Candidate B



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In a survey, 20% favored candidate A, 30% favored candidate 02 Jul 2005, 12:44
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AJ, I see you are getting yourself up to speed with those set problems - good stuff. Knowing how to solve this kind of problems is very important for getting a good math score.

AUBUC + ~(AUBUC) = A + B + C - AnB - AnC -BnC + AnBnC + ~(AUBUC)

we are looking for AnB + AnC + BnC + AnBnC

so S1 gives us ~(AUBUC) = 100 -80 = 20% (didn't favor anyone)
80 = 20 + 30 + 50 - (AnB + AnC + BnC) + 5

so (AnB + AnC + BnC) = 25
and AnB + AnC + BnC + AnBnC = 25 +5 = 30% sufficient

S2 is insuff, we don't know ~(AUBUC)
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In a survey, 20% favored candidate A, 30% favored candidate 02 Jul 2005, 14:03
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Sparky,

Thanks. Yes, I've sort of learned the concepts and I'm trying to find some tough problems to solve. It'll take me constant practice, I think.
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rthothad
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In a survey, 20% favored candidate A, 30% favored candidate 02 Jul 2005, 17:15
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Sparky, Thx for the formula - made me remember something that I learnt decades ago.
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HowManyToGo
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In a survey, 20% favored candidate A, 30% favored candidate 03 Jul 2005, 07:20
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sparky


we are looking for AnB + AnC + BnC + AnBnC

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sparky, not that It makes a difference to the answer the question, but I think we need to find AnB + AnC + BnC -2(AnBnC).

HMTG.
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In a survey, 20% favored candidate A, 30% favored candidate 03 Jul 2005, 11:07
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HowManyToGo
sparky


we are looking for AnB + AnC + BnC + AnBnC


sparky, not that It makes a difference to the answer the question, but I think we need to find AnB + AnC + BnC -2(AnBnC).

HMTG.
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you are right, we are looking for
AnB~C + AnC~B + BnC~A + ABC



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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