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In a town there are 60% married Males, 40% married Females. What is

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In a town there are 60% married Males, 40% married Females. What is [#permalink]

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New post 07 Nov 2017, 21:42
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Question Stats:

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In a town there are 60% Males married to 40% Females. What is the % of married people in town?

A. 20%
B. 30%
C. 40%
D. 48%
E. 50%

Source Experts' Global.
[Reveal] Spoiler: OA

Last edited by chetan2u on 12 Nov 2017, 07:31, edited 1 time in total.
formatted the Q

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Re: In a town there are 60% married Males, 40% married Females. What is [#permalink]

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New post 07 Nov 2017, 21:52
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Option E
Suppose 100 males are there. From question 60 are married.
Correspondingly 60 females has to be married and the total females are 150.

Hence % married =(60+60)/(100+150)
=48%

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Re: In a town there are 60% married Males, 40% married Females. What is [#permalink]

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New post 08 Nov 2017, 07:56
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Sangeeta2018 wrote:
In a town there are 60% married Males, 40% married Females. What is the % married?

A. 20%
B. 30%
C. 40%
D. 48%
E. 50%

Source Experts' Global.

This question is a bit sneaky. You cannot use 100 as the number of both men and women.

When two populations should sum to 100, but each has a different percentage of the same "property" (being married), that is a clue: you can use 100 as a base, with a percent, for only one of the two populations.

Assign a number to men. 60 percent are married = a number. That is also the number of married women. Then find total number of women (using 40%). There are NOT 100 women total.

Assuming all men are married to women and vice versa:

1) What number of married men AND women?

Let there be 100 men
60 percent of men are married (to women) =
60 married men AND
60 married women

2) Total population?

100 men

Total number of women?
60 married women = 40% of all women, W
60 = .40W
\(\frac{60}{.4}=\) W
W = 150

Total: (100 + 150) = 250

Married: (60 + 60) = 120

3) Percent married?

\(\frac{120}{250} * 100 = (.48 * 100) =\) 48 percent

Answer D

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Re: In a town there are 60% married Males, 40% married Females. What is [#permalink]

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New post 12 Nov 2017, 07:17
Sangeeta2018 wrote:
In a town there are 60% married Males, 40% married Females. What is the % married?

A. 20%
B. 30%
C. 40%
D. 48%
E. 50%


We are assuming here that all the males are married to the females who are in the town and vice versa (that is, no male or female has a spouse who lives out of town). Thus, the number of married males must equal the number of married females. If we let the total number of males = m and the total number of females = f, we have:

0.6m = 0.4f

6m = 4f

f = 6m/4 = 1.5m

Thus, the percentage of individuals in the town who are married can be expressed as:

(0.6m + 0.4f)/(m + f)

Let’s re-express this in terms of m only (recall that 0.4f = 0.6m and f = 1.5m):

(0.6m + 0.6m)/(m + 1.5m)

1.2m/2.5m

1.2/2.5

12/25 = 48/100 = 48%

Answer: D
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Re: In a town there are 60% married Males, 40% married Females. What is [#permalink]

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New post 12 Nov 2017, 07:29
Sangeeta2018 wrote:
In a town there are 60% married Males, 40% married Females. What is the % married?

A. 20%
B. 30%
C. 40%
D. 48%
E. 50%

Source Experts' Global.


A poor question..
To answer you would also require the RATIO of males and females....

but lets assume that these are married to each other and then answer...

60% males are married to 40% females, so \(\frac{60m}{100}=\frac{40f}{100}...\frac{f}{m}=\frac{3}{2}\)

now we can use weighted average method..
average = \(40+(60-40)*\frac{2}{2+3}=40+\frac{20*2}{5}=40+8=48\)

D
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Re: In a town there are 60% married Males, 40% married Females. What is   [#permalink] 12 Nov 2017, 07:29
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