Let number of female students in first semester = F, number of male students in first semester, M = F - x
Number of female students in second semester = 1.1F, number of male students in second semester = (F - x)(1.22)
We know the difference between female students and male students in both semesters is the same.
Therefore: F - (F - x) = 1.1F - (F - x)(1.22)
= x = 1.1F - 1.22F + 1.22x
= x = -0.12F + 1.22x
= (-0.22)x = -0.12F
= x = 6/11*F
Putting value of x in the number of male students in the first semester we get, M = F - 6/11*F = 5/11*F
Now to find the percentage by which the number of students in total increased:
(F(1.1) + 5F/11(1.22) - F - 5F/11) - (F - 5F/11))/ (F + 5F/11)
= ((0.1)F + (0.22)5F/11)/(16F/11)
=((0.1)F + (0.1)F)/(16F/11)
=(0.2F)/(16F/11)
=2.2/16
=0.1375
Multiplying by hundred we get
13.75% or 13 3/4% increase, the answer is E