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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
53% (01:53) correct
47%
(01:42)
wrong
based on 57
sessions
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Not Attempted Yet
In baseball, a pitcher’s Earned Run Average, \(A\), is calculated by means of the formula \( A = \frac{9R}{I}\), where \(R\) is the number of runs the pitcher has allowed and \(I\) is the number of innings pitched by the pitcher. Has pitcher X pitched more innings than pitcher Y?
(1) Pitcher X has a lower Earned Run Average than pitcher Y.
(2) Pitcher X has allowed fewer runs than Pitcher Y.
(1) Pitcher X has a lower Earned Run Average than pitcher Y.
(2) Pitcher X has allowed fewer runs than Pitcher Y.
Updated on: 09 Nov 2025, 01:47
Originally posted by gmatophobia on 09 Nov 2025, 01:43.
Last edited by gmatophobia on 09 Nov 2025, 01:47, edited 1 time in total.
Last edited by gmatophobia on 09 Nov 2025, 01:47, edited 1 time in total.
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MartyMurray
\(A = \frac{9R}{I}\)
From the information on the question stem, we can conclude that both \(R\) and \(I\) are natural numbers
\(A_X = \frac{9R_X}{I_X}\)
\(A_Y = \frac{9R_Y}{I_Y}\)
Question: \(I_X > I_Y\)
As \(I_Y\) is positive, dividing both sides by \(I_Y\) we get
\(\frac{I_X}{I_Y} > 1\)
Statement 1
(1) Pitcher X has a lower Earned Run Average than pitcher Y.
\(A_X < A_Y\)
\(\frac{9R_X}{I_X} < \frac{9R_Y}{I_Y}\)
\(\frac{I_X}{I_Y} > \frac{R_Y}{R_X}\)
This statement doesn't help with the information whether \(\frac{I_X}{I_Y} > 1\)
For example, if \(\frac{I_X}{I_Y}\) = 0.75 , the answer to the question "Whether \(\frac{I_X}{I_Y} > 1\) ?" is No, on the other hand, if \(\frac{I_X}{I_Y}\) = 2, the answer to the question "Whether \(\frac{I_X}{I_Y} > 1\) ?" is Yes
As both possibility exisits, we can eliminate A and D.
(2) Pitcher X has allowed fewer runs than Pitcher Y.
Inference, \(R_X < R_Y\)
The statement doesn't provide any information on the relationship between \(I_X\) and \(I_Y\), hence we can eliminate B
Combined
\(\frac{I_X}{I_Y} > \frac{R_Y}{R_X}\)
\(R_X < R_Y\)
From Statement 2, we can infer that
\(\frac{R_Y}{R_X} > 1\)
However, we don't know whether \( \frac{I_X}{I_Y}\) is greater than 1
Ex:
\(R_Y = 6\)
\(R_X = 3\)
\(I_X = 3\)
\(I_Y = 4\)
\(\frac{I_X}{I_Y} > 1 ? \), the answer is No
\(R_Y = 6\)
\(R_X = 3\)
\(I_X = 4\)
\(I_Y = 3\)
\(\frac{I_X}{I_Y} > 1 ? \), the answer is Yes
Hence, the statments combined is not sufficient to answer the question asked.
Option E
