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15 Apr 2020, 06:11
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C
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80% (02:05) correct
20%
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In class A, the ratio of boys to girls is 2 : 3. In class B the ratio of boys to girls is 4 : 5. If the ratio of boys to girls in both classes put together is 3 : 4, what is the ratio of number of girls in class A to number of girls in class B?
A. 1/5
B. 2/5
C. 3/5
D. 4/5
E. 5/6
Are You Up For the Challenge: 700 Level Questions
A. 1/5
B. 2/5
C. 3/5
D. 4/5
E. 5/6
Are You Up For the Challenge: 700 Level Questions
15 Apr 2020, 06:45
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Number Picking Approach
Let's say that:
--> 2 boys and 3 girls in Class A
\(\frac{B}{G} = \frac{2}{3}\)
--> 4 boys and 5 girls in Class B
\(\frac{B}{G}= \frac{4}{5}\)
Taken together ClassA and ClassB,
\(\frac{B}{G}= \frac{2+4}{3+5}= \frac{6}{8}= \frac{3}{4 }\)
--> \(\frac{Girls_{ClassA}}{ Girls_{ClassB}}= \frac{3}{5 }\)
Answer (C).
Let's say that:
--> 2 boys and 3 girls in Class A
\(\frac{B}{G} = \frac{2}{3}\)
--> 4 boys and 5 girls in Class B
\(\frac{B}{G}= \frac{4}{5}\)
Taken together ClassA and ClassB,
\(\frac{B}{G}= \frac{2+4}{3+5}= \frac{6}{8}= \frac{3}{4 }\)
--> \(\frac{Girls_{ClassA}}{ Girls_{ClassB}}= \frac{3}{5 }\)
Answer (C).
15 Apr 2020, 06:48
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In class \(A\), \(B:G=\frac{2}{3}\) This means that there are \(2a\) boys and \(3a\) girls in class \(A\), whereby \(a\) is a positive integer.
In class \(B\), \(B:G=\frac{4}{5}\) This means that there are \(4b\) boys and \(5b\) girls in class \(B\), whereby \(b\) is a positive integer.
Cummulatively, the ratio of Boys to Girls in both classes is \(\frac{3}{4}\)
Total boys in both class \(A\) and \(B\) \(= 2a+4b\)
Total girls in both class \(A\) and \(B\) \(= 3a+5b\)
\(= \frac{2a+4b}{3a+5b}=\frac{3}{4}\)
\(8a+16b=9a+15b\)
\(a=b\)
Ratio of girls in class \(A\) to girls in class in \(B\) \(= \frac{3a}{5a} = \frac{3}{5}\)
The answer is therefore C.
In class \(B\), \(B:G=\frac{4}{5}\) This means that there are \(4b\) boys and \(5b\) girls in class \(B\), whereby \(b\) is a positive integer.
Cummulatively, the ratio of Boys to Girls in both classes is \(\frac{3}{4}\)
Total boys in both class \(A\) and \(B\) \(= 2a+4b\)
Total girls in both class \(A\) and \(B\) \(= 3a+5b\)
\(= \frac{2a+4b}{3a+5b}=\frac{3}{4}\)
\(8a+16b=9a+15b\)
\(a=b\)
Ratio of girls in class \(A\) to girls in class in \(B\) \(= \frac{3a}{5a} = \frac{3}{5}\)
The answer is therefore C.
