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04 Mar 2020, 05:48
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
29% (01:26) correct
71%
(02:30)
wrong
based on 7
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There are 5 digits (0,1,2,3,4,5) .Assume that repetation of digits are not allowed & 4 Digit numbers are to be formed, in how many cases does 2 come before 4 & 4 come before 5?
A. 16
B. 24
C. 34
D. 48
E. 96
Source - TIME
A. 16
B. 24
C. 34
D. 48
E. 96
Source - TIME
This Question is Locked Due to Poor Quality
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05 Mar 2020, 00:08
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J2S2019
There are 5 digits (0,1,2,3,4,5) .Assume that repetition of digits are not allowed & 4 Digit numbers are to be formed, in how many cases does 2 come before 4 & 4 come before 5?
A. 16
B. 24
C. 34
D. 48
E. 96
Source - TIME
A. 16
B. 24
C. 34
D. 48
E. 96
Source - TIME
Please be careful with questions you post. This is second time that I have seen your questions have faulty answer options..
As per the question, the 4-digit number has to have 245 in the sequence, so we are left with one place to be filled up by 0, 1 or 3..
0.... 2_4_5_......0 can be any of the 3 positions
1.... _2_4_5_......1 can be any of the 4 positions
3.... _2_4_5_......3 again can be any of the 4 positions
Total 3+4+4=11
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
Looking for better-quality questions? Check out the 'Similar Questions' block below
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