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Bunuel
In how many ways can 3 different prizes be distributed among 5 students when a student may get any number of prizes?

(A) 60
(B) 100
(C) 120
(D) 124
(E) 125

Prices: 5 x 5 x 5 = 125

IMO E
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KarishmaB help me plz

Why can't we think this way....Any student can choose any number of prizes... so one can choose 0-3 prizes that is one has 4 options to choose. first student has 4 ways to choose.. second student has also 4 ways to choose and so on..so ways are: 4*4*4*4*4....why this thinking is wrong?

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KarishmaB help me plz

Why can't we think this way....Any student can choose any number of prizes... so one can choose 0-3 prizes that is one has 4 options to choose. first student has 4 ways to choose.. second student has also 4 ways to choose and so on..so ways are: 4*4*4*4*4....why this thinking is wrong?

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The available choices for the second student are dependent on what first student chose. The available choices for third student depends on what first two students chose etc. So it is not 4*4*4*4*4.

If first student chooses no prize, second student has 4 options (0/1/2/3).
If first student chooses 1 prize, second students has 3 options (0/1/2).
etc.
Also, in this case, it is possible that no student may claim any prize which is not acceptable.

All 3 prizes need to be distributed. For each prize, we must choose 1 of 5 students.
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Prizes will goes to student, so every prize can go to 5 different student.
If prizes be P1,P2,P3
than for students S1,S2,S3,S4,S5.
Prize P1 can be given to any of the 5 students.
Prize P2 can be given to any of the 5 students.
Similarly Prize P3 can be given to any of the 5 students.
Hence total choices will be 5*5*5= 125.

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Hello! I don't get the solution. Can one student get 2 prizes or am I reading badly the statement?
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Hello! I don't get the solution. Can one student get 2 prizes or am I reading badly the statement?
Check the highlighted part:

­In how many ways can 3 different prizes be distributed among 5 students when a student may get any number of prizes?
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